Re: mfinit with trivial character

I'm sorry. This was a very silly question. Please ignore it.

I apologise again,


John

On Mon, Oct 27, 2025 at 5:15 AM John Duncan <[email protected]>
wrote:

> Hello,
>
> Using Version 2.17.2, the input
>
> mfinit( [ n, k, Mod( 0, n ) ], s )
>
> for given n, k and s, seems to return an error whenever n>2.
>
> Would it be reasonable to define it to coincide with
>
> mfinit( [ n, k ], s )
>
> ?
>
> Yours faithfully,
>
>
> John
>
>
>