Re: question on qfbsolve(Qfb(1,0,1),[N,F],3) call

Thanks Karim for that tip.

My execution time at n=11789 dropped from 103.212 secs to 84.324 secs 
which is a 22.4% improvement using the [N,F] to qfbsolve() for b=11789 
to 117,890.

On 4/4/26 07:23, Karim Belabas wrote:
> * American Citizen [2026-04-04 02:36]:
> [...]
>> Suppose I have
>>
>>     b = 741336
>>     c = 362900
>>
>>     How can I successfully merge the factor matrices for b and c into the
>> final factor matrix for (2*b^2*c^2)^2 or 4*b^4*c^4 ?
> [...]
>
> Use matreduce and play directly with exponents.
>
> ? B = factor(b); C = factor(c);
> ? matreduce(matconcat([B,C]~)) == factor(b*c)
> %2 = 1
> ? B[,2] *= 4; C[,2] *= 4;
> ? matreduce(matconcat([factor(4), B,C]~)) == factor(4*b^4*c^4)
> %3 = 1
>
> Cheers,
>
>      K.B.