Re: Can you tell me function name that means 'Entry Point: 0x11000000' ?

Hi,

> On 21 Mar 2014, at 11:33, Taeung <[email protected]> wrote:
> 
> Hello, l4 hacker.
> 
> 
> I'm trying to boot "Hello world / L4/ Fiasco" on Freescale i.MX6 Quad SABRE SD board(Cortex-A9, ARMv7).
> 
> I'm using 'u-boot' and 'uImage'.
> So, i build uimage by "make uimage E=hello ~...".
> And i've try to booting it on Freescale i.MX6q_sabre_sd board.
> But i did not it because stoped at "Starting kernel ..." !!

Probably you selected the wrong UART, so the system is not printing something on the serial line. Make sure you have the right UART driver for your platform and make sure you have selected the right one. Usually there are more than one UARTs and only one is connected to you serial line. You can also check Linux to see which UART it uses.

> MMC read: dev # 2, block # 2048, count 8192 ... 8192 blocks read: OK
> ## Booting kernel from Legacy Image at 10800000 ...
>   Image Name:   L4 Image #2
>   Image Type:   ARM Linux Kernel Image (uncompressed)
>   Data Size:    868352 Bytes = 848 kB
>   Load Address: 11000000
>   Entry Point:  11000000
>   Loading Kernel Image ... OK
> OK
> 
> Starting kernel ...
> 
> 
> uimage's file name is "bootstrap_hello.uimage".
> "bootstrap_hello.uimage" has information such as
> "bootstrap_hello.uimage: u-boot legacy uImage, L4 Image #2, Linux/ARM, OS Kernel Image (Not compressed), 868352 bytes,
> Thu Mar 20 13:14:42 2014, Load Address: 0x11000000, Entry Point: 0x11000000, Header CRC: 0xBEA251F3, Data CRC: 0xA0217B7D"
> 
> I have a question.
> 
> Can you tell me function name that means 'Entry Point: 0x11000000' ?

In the uimage format the entry point is defined as the address where uboot should start, as the name implies, the execution of the image.


Matthias.