Re: Using a second UART to control a serial device

Hi,

> How does the 'no access' show? J12 is described as having UART7 so I'd
> assume the UART is there. (UART4 starts on a new page, you have mapped
> that too?)
If I try to read any register like I usally do:
       char sc = regs->read<unsigned char>(LCR);
       printf("0x0C LCR: %#010x\n", sc);
All i get is 0x00 even if i try writing to it before. I have had the 
exact same problem with UART0-3 before manually adjusting the Registers 
to their actual offsets or setting the shift parameter of 
Io_register_block_mmio to 2. So its actually like I'm looking at/writing 
to the wrong places.
I map the memory similar to the serial-drv example only ever one UART at 
a time:
    #define IRQ_NUM 52                 //currently set to UART7, 36 for 
UART3
    #define UART_BASE 0x01C29C00       //currently set to UART7, 
0x01C28C00 for UART3

bool Maestro_server::init()
    {
       printf("init start\n");
       l4_addr_t virt_base = 0;

       if (l4io_request_iomem((l4_addr_t)UART_BASE, 0x0400, 
L4IO_MEM_NONCACHED, &virt_base))
         {
           printf("maestro-drv: request io-memory from l4io failed.\n");
           return false;
         }
       printf("maestro-drv: virtual base at:%lx\n", virt_base);


       L4::Io_register_block_mmio *regs = new 
L4::Io_register_block_mmio(virt_base, 2);
       printf("registered regs\n");

       _uart = new (malloc(sizeof(L4::Uart_bpi16550))) 
L4::Uart_bpi16550((unsigned long) 115200);
       printf("malloc for _uart\n");
       printf("\n");

       if(!(_uart->startup(regs))){
	     printf("failed to startup uart regs!\n");
       }

}
> Hmm, does it work with on Linux, i.e. it's not something
> hardware-related?

I have tested the UARTS with the Bananian linux and they work just fine, 
so it cant be hardware-related.

Regards,
Clemens