Re: How to get the rendered dom element's coordinate infos in JAVAXPCOM
网事随风 <[email protected]> Mon, 19 May 2008 19:25:17 -0700 (PDT)
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On 5月20日, 上午10时18分, 网事随风 <[email protected]> wrote: > I want to know the exact position (X, Y, width and height) of dom > element of a HTML. How can I achive this using JAVAXPCOM? I provide a sample code snippet below, which can output some element's position info by executing JavaScript. How can I achieve the same goal using pure Java code in JAVAXPCOM? public class Test { public static void main(String [] args) { final String html = "<html><title>Snippet</title><body><p id='myid'>Best Friends</p><p id='myid2'>Cat and Dog</p></body></ html>"; Display display = new Display(); final Shell shell = new Shell(display); shell.setLayout(new FillLayout()); final Browser browser; try { browser = new Browser(shell, SWT.MOZILLA); } catch (SWTError e) { System.out.println("Could not instantiate Browser: " + e.getMessage()); return; } browser.addStatusTextListener(new StatusTextListener() { public void changed(StatusTextEvent event) { browser.setData("query", event.text); } }); browser.addProgressListener(new ProgressListener() { public void changed(ProgressEvent event) { } public void completed(ProgressEvent event) { boolean result = browser.execute("window.status = document.getBoxObjectFor( document.getElementById('myid') ).screenX;"); if (!result) { /* Script may fail or may not be supported on certain platforms. */ System.out.println("Script was not executed."); return; } String value = (String)browser.getData("query"); System.out.println("Node value: "+value); } }); /* Load an HTML document */ browser.setText(html); //shell.open(); while (!shell.isDisposed()) { if (!display.readAndDispatch()) display.sleep(); } display.dispose(); } } _______________________________________________ dev-tech-java mailing list [email protected] https://lists.mozilla.org/listinfo/dev-tech-java