Re: How to display img using XSLT
[email protected] 12 Mar 2007 09:35:57 -0700
| Newsgroups | gmane.comp.mozilla.devel.layout.xslt |
|---|---|
| Organization | http://groups.google.com |
| Message-ID | <[email protected]> |
On Feb 20, 12:34 am, "Chuck" <[email protected]> wrote: > Hi, > > I am new to XSLT and I have an XML file in the format given below. For > each item, I would like to diplay the img as a thumbnail (with the src > from XML) and the title next to the image in each line: > ================ > <?xml version="1.0" encoding="ISO-8859-1"?> > <?xml-stylesheet type="text/xsl" href="test3.xsl"?> > <html xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > xsl:version="1.0"> > <item> > <title>CNN Title </title> > <link>http://www.cnn.com</link> > <description><img src="cnnImage.jpg" />This is CNN home page</ > description> > </item> > <item> > <title>Yahoo title</title> > <link>http://www.yahoo.com</link> > <description><img src="yahooImage.jpg" />This is yahoo home page</ > description> > </item> > </html> > ============== > My code is this, however the image is not being displayed: > ---------------------------- > <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/ > Transform"> > <xsl:output method="html" /> > <xsl:template match="/"> > <link rel="stylesheet" href="style.css" type="text/css" /> > <xsl:for-each select="html/item"> > <div> > <span> > <img width="120" height="90"> > <xsl:attribute name="src"><xsl:value-of select="@src"/></ > xsl:attribute> > </img> > </span> > <span> > <a class="link" style="valign:top"> > <xsl:attribute name="href"><xsl:value-of select="link" /></ > xsl:attribute> > <xsl:value-of select="title" /> > </a> > </span> > </div> > <br /> > </xsl:for-each> > </xsl:template> > </xsl:stylesheet> > ------------------- > I would really appreciate any help regarding this. > Thanks Your statement <xsl:attribute name="src"><xsl:value-of select="@src"/></ xsl:attribute> is incorrect. The context node is the <item> element, but the src attribute is not on the <item> element; it's on <description><img>. So you want <xsl:attribute name="src"><xsl:value-of select="description/img/ @src"/></xsl:attribute> Lars