Re: xsl:output method=xhtml
twostepted <[email protected]> Mon, 31 Dec 2007 05:45:32 -0800 (PST)
| Newsgroups | gmane.comp.mozilla.devel.layout.xslt |
|---|---|
| Organization | http://groups.google.com |
| Message-ID | <8a477588-a643-4791-b2cd-e0d2230d0740@e10g2000prf.googlegroups.com> |
Anthony, Thanks for the reply. I've responded inline below. > You need method="xml". You should also consider using the doctype-public > and doctype-system to specify the XHTML doc type. For example:- When I use method="xml", I am able to see the namespaces, but I can't the rendered xforms controls. > <xsl:output method="xml" > doctype-system="http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd" > doctype-public="-//W3C//DTD XHTML 1.0 Transitional//EN" > indent="yes" /> Thanks, I'd already included these (doctype-system & doctype- public). So I need some help with this. Let me know if I should post any content or other info. Thanks, Travis