how to get the detailed error info about XSL

shiwudao <[email protected]> Thu, 31 Jan 2008 09:27:43 +0000
Newsgroups gmane.comp.mozilla.devel.layout.xslt
Message-ID <[email protected]>


Hi, Anybody knows how to get detailed error message when I use Javascript/XSLTProcessor() under Firefox.
 For example, I wrote a XSL1.0 XSL file like:
   ... < xsl:if test=" $ level > 2 "> ...
There should be " > ", but I wrote ">"

When I call
var xsltProcessor = new XSLTProcessor();
xsltProcessor.importStylesheet(myxsl);

There will throw an exception with the error message:
 XSLT-Component returned failure code: 0x80600001 [nsIXSLTProcessor.importStylesheet]

I do not think this information can give more about the error reason.

But in the error console of FireFox, it will display an error message like:

error: source:http s:// xxx.xxx.xxx.com:xxx/xxx/xsl/test.xsl
line:45 column:27source: --------------------------^

The question is how can get this error message by javascript? thank you.

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