Re: content not generated from template

Brian Frein <[email protected]>
Newsgroups gmane.comp.mozilla.devel.rdf
Organization Another Netscape Collabra Server User
Message-ID <[email protected]>
so if I have the following datasource,

----
<?xml version="1.0"?>
<rdf:RDF xmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#"
   xmlns:ns="http://www.foo.org/resources/">
   <rdf:Description rdf:about="http://www.foo.org/resources#Node">
     <ns:property>Value</ns:property>
   </rdf:Description>
</rdf:RDF>
----

you mean that I cannot use a template to extract de "value" of 
"property"? How should be the datasource?

(this changes has been updated into moz1.7, hasn't it? because I *CAN* 
use a template in moz1.6)

tx.

Neil Deakin wrote:

> Brian Frein wrote:
> 
>> The containment attribute:
>> "his attribute specifies RDF properties that indicate that a resource 
>> is a container"
>>
>> I have only one element in the datasource, but it is *NOT* a container!
>>
> 
> The container resource and generated member resources must be different.
> 
> Templates are used to iterate over a set of children, although they 
> don't have to be children of a container. If you just want to display 
> some fields from one resource you cannot use a template.
> 
> / Neil
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