Re: How to open "file://"-RDF, change it and flush it to somewhere else?

Manuel Reimer wrote:
> Hello,
> 
> what do I have to do to open a "file://"-RDF and save it, after 
> changing, to somewhere else *without* changing the initially opened file?
> 
> Currently I use this code:
> 
> | var rdfService = Components.classes["@mozilla.org/rdf/rdf-service;1"].
> |                    getService(Components.interfaces.nsIRDFService);
> | | var ds=rdfService.GetDataSourceBlocking("file:///tmp/inputtest.rdf");
> | | var subject = rdfService.GetResource("http://www.example.com/test");
> | var predicate = |      
> rdfService.GetResource("http://www.example.com/rdf#name");
> | var name = rdfService.GetLiteral("This is a test");
> | | ds.Assert(subject, predicate, name, true);
> | | ds.QueryInterface(Components.interfaces.nsIRDFRemoteDataSource);
> | ds.FlushTo("file:///tmp/outtest.rdf");
> | rdfService.UnregisterDataSource(ds);
> 
> This saves my output file, but always changes the input file, too.

Yes, that's what it's supposed to do.

The only way that I see is using a non-file datasource for your 
modifications. There are several ways for that, faking a protocol or 
using a in mem ds and doing parsing and serializing by hand.

Maybe others, too.

Axel