Re: getting plain text from the xslt processor...
Emmanouil Batsis <[email protected]>
| Newsgroups | gmane.comp.mozilla.devel.xml |
|---|---|
| Organization | Another Netscape Collabra Server User |
| Message-ID | <[email protected]> |
I havent seen your code but i believe the result of it must be a Document object. You can only have that if the transformation result serialization is a well-formed XML document. The wrapper is there for just that. Manos Rui Paiva wrote: > Hi everyone, > > I am trying to get a plain text string as a result of a xsltransform, but I > am getting instead > <transformiix:result xmlns:transformiix="http://......">My/text/message > </transformiix:result> > > using the following xslTransform... > > <?xml version="1.0" encoding="ISO-8859-1"?> > <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > version="2.0"> > > <xsl:output method="text" version="1.0" encoding="ISO-8859-1" /> > > <xsl:template match="/" > > > <xsl:value-of select=" concat ( //FileList [ @currentFileList = > 'true' ]/RelativePath/text(), '/' ) " /> > <xsl:value-of select=" //FileList [ @currentFileList = > 'true' ]/FileName/text() " /> > > </xsl:template > > > </xsl:stylesheet> > > How do I get rid of the <transformiix:result> element and keep only element > text ? > > Thanks > > Rui > >