[Spirit Development] Bug using attr in variant

The following rule is clearly glitch-ed:

boost::spirit::qi::rule<std::string::iterator,std::string()> rule =
((string("note") >> ":") | attr(std::string(""))) >> "note";

When I give it the input "note" the first branch (string("note") >>
":") fails because there is no ":" in the input string.  The
attr(std::string("")) should then pass the empty string as an
attribute.  It doesn't.  attr(std::string("")) passed the string
"note" to the return value.

Here is the code that illustrates the bug:


#include <boost/spirit/include/qi.hpp>
#include <boost/fusion/adapted/struct/adapt_struct.hpp>
#include <boost/spirit/include/phoenix_fusion.hpp>
#include <boost/spirit/include/phoenix_operator.hpp>
#include <boost/spirit/include/qi_as.hpp>
#include <string>

int main()
{
  using namespace boost::spirit::qi;
  using namespace boost::phoenix;
  std::string input = "note";
  boost::spirit::qi::rule<std::string::iterator,std::string()> rule;
  rule %= ((string("note") >> ":") | attr(std::string(""))) >> "note";
  std::string output;
  bool passed = parse(input.begin(),input.end(),rule > eoi,output);
  assert(passed);
  std::cout<<"output: '"<<output<<"'"<<std::endl; //should be nothing
}

Thanks
--Robert Nelson

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#include <boost/spirit/include/qi.hpp>
#include <boost/fusion/adapted/struct/adapt_struct.hpp>
#include <boost/spirit/include/phoenix_fusion.hpp>
#include <boost/spirit/include/phoenix_operator.hpp>
#include <boost/spirit/include/qi_as.hpp>
#include <string>

int main()
{
  using namespace boost::spirit::qi;
  using namespace boost::phoenix;
  std::string input = "note";
  boost::spirit::qi::rule<std::string::iterator,std::string()> rule;
  rule %= ((string("note") >> ":") | attr(std::string(""))) >> "note";
  std::string output;
  bool passed = parse(input.begin(),input.end(),rule > eoi,output);
  assert(passed);
  std::cout<<"output: '"<<output<<"'"<<std::endl; //should be nothing
}