Re: Problem w/query - again

At 12:48 AM 2/10/2012, Amit Tandon wrote:
>Dear Ethan
>
>The line you are getting is because the 
>$_POST[fieldname] is blank. So for the following line
>Â if ( ! empty( $_POST['field'] ) )
>change it to
>Â if ( ! empty( $_POST["$field"] ) )
>
>Your line : Program is searxchinbg for variable name field
>New line : The Program is seacging for varable 
>stored in $field. Rember to use double quotes
>
>And to verify the value echo $_POST["$field"] before your if line i.e.
>Â if ( ! empty( $_POST["$field"] ) )
>Â  Â Â
>============
>regds
>amit
>
>"The difference between fiction and reality? Fiction has to make sense."
>
>
>On Fri, Feb 10, 2012 at 11:04 AM, Ethan 
>Rosenberg <<mailto:[email protected]>[email protected]> wrote:
>At 12:13 AM 2/10/2012, Amit Tandon wrote:
>Dear Ethan
>
>It seems you are trying to build a query.But you are not getting field
>names. If you required field names then change the following line to
>
>foreach ( $allowed_fields AS $field => $_POST['field'])
>to
>foreach ( $allowed_fields AS $field)
>
>This would convert the variable field to value. In yoyr line the variable
>field is treated as array index
>============
>regds
>amit
>
>"The difference between fiction and reality? Fiction has to make sense."
>
><snip>
>
> >
> > Advice and help please.
> >
> > Thanks.
> >
> >
> > Ethan
> > PHP Database Mailing List (<http://www.php.net/>http://www.php.net/)
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Amit -

Thanks.

Tried your edit.  Still does not work.

Ethan

> >
> >
>
>
>Amit -
>
>Thanks.
>
>Tried it. Â Still does not work.
>
>This is the query I get:
>
>
>select * from Intake3 where  1
>
>Ethan
>



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