Re: Help with If else if

On Tue, 13 Mar 2012 21:23:57 +0530, Gu®u <[email protected]> sent:

> No Michael, your code is also not working. What you have understood is
> correct. let me explain it to others too.
>
> If variable twitter and facebook are empty don't echo anything,
>
> if variable twitter has a value and facebook is empty echo out only twitter,
>
> if variable twitter has no value and facebook has a value echo out facebook
> only,
>
> and finally if both has values echo out both.
>
> Basically I want to echo out only if there is some value in the database.
> But in my case both the images are echoing out.

For probably the bazillionth time, PUT REPLIES ON THE BOTTOM

>
>
>
>
> On Tue, Mar 13, 2012 at 8:54 PM, Michael Stowe <[email protected]> wrote:
>
>> From looking at your code, the issue is that your if statements are
>> checking for the same criteria as your else statements, meaning that if the
>> string is empty ("") the if statements will be triggered, and since the if
>> statements are true, the elseif statement will not be.  Or if the string
>> isn't empty, neither the if or the elseif statements will be triggered,
>> causing the else statement to be activated.  Either way, the images would
>> be printed out. *
>> *
>> *
>> *
>> *Did you mean to do this?*
>>
>> <?php
>> if($search->plugin->ListViewValue() == "" &&
>> $search->facebook->ListViewValue() == "") {
>>     // Neither one has a value
>> } elseif ($search->plugin->ListViewValue() != "" &&
>> $search->facebook->ListViewValue() != "") {
>>     // Both have a Value
>>     echo '<a href="' . $search->plugin->ListViewValue() . '"><img
>>     src="images/twitter.gif" width="22" height="23"/></a></a>' . '<a
>>     href="' . $search->facebook->ListViewValue() . '"><img
>>     src="images/facebook.gif" width="22" height="23"/></a></a>';
>> } elseif ($search->plugin->ListViewValue() != "") {
>>     // Twitter has a value
>> } else {
>>     // Facebook has a value (only possible option left)
>>     echo '<a href="' . $search->facebook->ListViewValue() . '"><img
>>     src="images/facebook.gif" width="22" height="23"/></a></a>';
>> }
>> ?>
>>
>>
>>
>> Hope that helps,
>> Mike
>>
>>
>>
>> On Tue, Mar 13, 2012 at 9:44 AM, Matijn Woudt <[email protected]> wrote:
>>
>>> On Tue, Mar 13, 2012 at 3:06 PM, Gu®u <[email protected]> wrote:
>>> > The issue is both the images are echoing and no if else statement is
>>> > working.
>>> >
>>>
>>> First of all, please bottom post on this (and probably any) mailing list.
>>>
>>> You should perhaps provide what the contents of
>>> $search->plugin->ListViewValue()=="" and
>>> $search->facebook->ListViewValue()=="" is.
>>> Though, if I understood you correctly, it would be as simple as:
>>> $facebookEnabled = $search->facebook->ListViewValue()!="";
>>> $twitterEnabled = $search->plugin->ListViewValue()!="";
>>> if($facebookEnabled)
>>>          {
>>>
>>>          echo '<a href="'.$search->facebook->ListViewValue().'"><img
>>> src="images/facebook.gif" width="22" height="23"/></a></a>';
>>>         }
>>>          if($twitterEnabled)
>>>          {
>>>
>>>         echo '<a href="'.$search->plugin->ListViewValue().'"><img
>>> src="images/twitter.gif" width="22" height="23"/></a></a>';
>>>         }
>>>
>>> - Matijn
>>>
>>> --
>>> PHP Database Mailing List (http://www.php.net/)
>>> To unsubscribe, visit: http://www.php.net/unsub.php
>>>
>>>
>>
>>
>> --
>> -----------------------
>>
>> "My command is this: Love each other as I
>> have loved you."                         John 15:12
>>
>> -----------------------
>>
>
>
>
> --
> *Best,
> *
> *Gu®u*
>

Recapitulating your pseudocode above, you don't need anything so complex:

if twitter is set:
    emit twitter image
if facebook is set:
    emit facebook image

The two seem completely independent of each other. Thus:

<?php
$twitter = $search->plugin->ListViewValue();
if (!empty($twitter)) {
    echo '<a href="'.$twitter.'"><img src="images/twitter.gif"  
width="22" height="23"/></a>';
}
$fb = $search->facebook->ListViewValue();
if (!empty($fb)) {
    echo '<a href="'.$fb.'"><img src="images/facebook.gif" width="22"  
height="23"/></a>';
}
?>

The above will give a twitter image+link if the twitter link is set,  
and a facebook image+link if facebook is set. You don't need to do  
anything special if both are set, or if neither is set, as they are  
completely independent of each other.

-- 
Tamara Temple
    aka tamouse__

May you never see a stranger's face in the mirror


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