Re: Re: Database Problems

Ethan Rosenberg <[email protected]>
Newsgroups gmane.comp.php.database
Message-ID <[email protected]>
At 04:21 PM 6/17/2012, Jim Giner wrote:

>"Ethan Rosenberg" <[email protected]> wrote in message
>news:[email protected]...
> > At 03:30 PM 6/17/2012, Jim Giner wrote:
> >>"Ethan Rosenberg" <[email protected]> wrote in message
> >>news:[email protected]...
> >> > Dear List -
> >> >
> >>
> >> >
> >> > The same query in a PHP program will only give me results for MedRec
> >> > 10003
> >> >
> >>
> >>why the "where 1" clause?  Do you know what that is for?
> > =================
> > Dear Jim
> >
> > Thanks
> >
> > As I understand, to enable me to concatenate phases to construct a query.
> >
> > The query does work in MySQL fro the terminal.
> >
> > Ethan
> >
>
>I don't think so.  All it does is return one record.  The where clause
>defines what you want returned.  A '1' returns one record, the first one.
>#10003
>
>I wonder why you think "where 1" enables concatenation??  A query (IN SIMPLE
>TERMS PEOPLE) is simply a SELECT ion of fields from a group of tables,with a
>WHERE clause to define the criteria to limit the rows, and an ORDER BY to
>sort the result set.  More complex queries can include GROUP BY when you are
>including summary operators such as SUM(fldname) or MAX(fldname), or a JOIN
>clause, or a host of other clauses that make sql so powerful.  In your case
>I think you copied a sample query that (they always seem to be displayed
>with a 'where 1' clause) and left the "1" on it.  To summarzie:
>
>SELECT a.fld1, a.fld2,b.fld1 from table1 as a, table2 as b WHERE a.key >100
>and a.key = b.key ORDER BY a.fld1
>
>I"m no expert, but hopefully this makes it a little less complex for you.
================

This is a suggestion I received from this list -
+++++++++++++++++++++
>>$query = "select * from Intake3 where ";
>
>Maybe I missed it, but you need to have a 1 after the where part in 
>your select.  So...
>
>$query = "SELECT * FROM Intake3 WHERE 1 ";
++++++++++++++++++++++++++++

I must stress that the query works from the terminal, and fails in 
the PHP code.

My question is why?????

Ethan



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