Re: Re: Problems w/ insert
Matt Pelmear <[email protected]>
| Newsgroups | gmane.comp.php.database |
|---|---|
| Message-ID | <[email protected]> |
Ethan, I am curious why you are using mysqli_stmt_bind_result() on a statement that is an INSERT query? I don't use mysqli, but as I read the documentation it seems to me that this method is intended to bind results from a SELECT query into variables so that you can simply call mysqli_stmt_fetch() in a loop and have the variables magically contain the data from the next row. Perhaps mysqli is confused because you are both mapping data to be bound (with mysqli_stmt_bind_param()) and to be returned (with mysqli_stmt_bind_result()) on the same INSERT query? If you are just trying to insert, you should only need mysqli_stmt_bind_param() (which, by my count, has one parameter too many right now in your code) and mysqli_stmt_execute() (and probably not mysql_stmt_bind_param() and mysql_stmt_fetch()). See "Example #2" here: http://us.php.net/manual/en/mysqli-stmt.execute.php -Matt On 09/10/2012 08:29 PM, Karl DeSaulniers wrote: > > On Sep 10, 2012, at 7:06 PM, Ethan Rosenberg, PhD wrote: > >> Dear list - >> >> Here is my code: >> >> $sql3 = "select max(Indx) from Visit3"; >> $result7 = mysqli_query($cxn, $sql3); >> $row7 = mysqli_fetch_array($result7, MYSQLI_BOTH); >> >> $Indx = $row7[0]; >> $sql2 = "INSERT INTO Visit3(Indx, Site, MedRec, Notes, >> Weight, BMI, Date) VALUES(?, ?, ?, ?, ?, ?, ? )"; >> >> mysqli_stmt_prepare( $stmt, $sql2 ); >> >> $_POST['Indx'] = $Indx; >> >> $_POST['Date'] = $Date; >> >> mysqli_stmt_bind_param($stmt, 'isisiis', $_POST['Indx'], >> $_POST['Site'], $_POST['MedRec'], >> $_POST['Notes'], $_POST['Weight'], $_POST['BMI'], >> $_POST['Date']); >> mysqli_execute($stmt); >> mysqli_stmt_bind_result($stmt, $_POST['Indx'], >> $_POST['Site'], $_POST['MedRec'], $_POST['Notes'], >> $_POST['Weight'], $_POST['BMI'], $_POST['Date']); >> *//The error is in this statement* >> mysqli_stmt_fetch($stmt); >> mysqli_stmt_close($stmt); >> >> *Warning: mysqli_stmt_bind_result(): Number of bind variables doesn't >> match number of fields in prepared statement* >> >> * >> * >> Help and advice, please. >> >> Ethan Rosenberg >> >> -- >> PHP Database Mailing List (http://www.php.net/) >> To unsubscribe, visit: http://www.php.net/unsub.php >> > > > Maybe right here there needs to be something? > > mysqli_stmt_bind_result($stmt, ?????, $_POST['Indx'], ... > > in the statement above you have. > > mysqli_stmt_bind_param($stmt, 'isisiis', $_POST['Indx'], ... > > what ever 'isisiis' is, you need to put somehting in your > ...bind_result() I think. > maybe.. > > mysqli_stmt_bind_result($stmt, '', $_POST['Indx'], > > or > > mysqli_stmt_bind_result($stmt, 'isisiis', $_POST['Indx'], > > sorry for not a more concrete answer. I am guessing a little. :) > HTH, > > Karl DeSaulniers > Design Drumm > http://designdrumm.com > > -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php