Re: Ajax

On Feb 20, 2013, at 10:13 PM, Ethan Rosenberg, PhD wrote:

>
> On 02/20/2013 10:49 PM, Karl DeSaulniers wrote:
>>
>> I think you need to set it here.
>>
>> <script type="text/javascript">
>>    $(document).ready(function(){
>>            $("#e1").dblclick(function(e) {
>>          var id = $(this).attr('id'); ///This was missing
>>                  $.post("testClickcallback.php",
>>                   {"custnum":cusn},  function getCustNo(id)
>>        {
>>            cno = 'cust'+id;
>>            cnm = "name"+id;
>>            cname = document.getElementById(cnm).innerHTML;
>>            cnum = document.getElementById(cno).innerHTML;
>>        alert("For customer "+cname+" the number is "+cnum);
>>            return;
>>        }
>> //    alert("subval");
>>  //alert(subval);
>>
>>  ,"html");
>> });
>>
>> });
>>
>> </script>
>>
>>
>> Best,
>> Karl
> =============
> Karl -
>> <snip>
>          var id = $(this).attr('id'); ///This was missing
>          alert(id);  // alert= undefined
>
> Ethan
>



FYI this is redundent.

   for($i=0; $i<10; $i++)
    {
        $k = $i ;  //this is not needed.
        $results .= "<tr><td id='name$i' >$names[$k] </td><td  id='nums 
$k'>$nums[$k]</td></tr>";

    }

You can just do.

for($i=0; $i<10; $i++)
    {
        $results .= "<tr><td id='name$i' >$names[$i] </td><td  id='nums 
$i'>$nums[$i]</td></tr>";

    }

unless you need
$k = $i +1;

on the javascript, I think the id is equaling 0 thats why $('#e1') is  
not working.
change to $('#e0') just for giggles. or try the &k = $i + 1

HTH,

Karl DeSaulniers
Design Drumm
http://designdrumm.com