Re: Problem with query
Jim Giner <[email protected]>
| Newsgroups | gmane.comp.php.database |
|---|---|
| Message-ID | <[email protected]> |
On 6/23/2013 2:31 PM, Ethan Rosenberg, PhD wrote: > Dear List - > > There is an error in my query, and I cannot find it. > > This fails: > > $_SESSION['Cust_Num'] = $_REQUEST['cnum']; > $_SESSION['CustNum'] = $_REQUEST['cnum']; > > echo "session<br />"; //this has the proper values > print_r($_SESSION); > > $sql10 = "select Balance, Payments, Charges, Date from Charges where > Cust_Num = $_SESSION[Cust_Num] order by Date"; > echo $sql10; //echos the correct query > $result10 = mysqli_query($cxn, $sql10); > var_dump($result1); // this returns NULL Against my better judgement, here I go again. Is this the "actual" code you executed, or is it once again a typeover? Your 1st error is in these two lines: > $result10 = mysqli_query($cxn, $sql10); > var_dump($result1); // this returns NULL Yes your dump returns null. And always will. Any further errors might be related to your non-standard syntax for the session variable. Per the manual, associative arrays using string indices should always use ' ' around them. They work (as mentioned in the manual) but are wrong. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php