Re: Corn job anomaly

> On Sep 20, 2016, at 10:09 PM, Peter Beckman <[email protected]> =
wrote:
>=20
> I suspect you are taking the pipe or semicolon literally.
>=20
> Drop the pipe and semicolon entirely. This should work:
>=20
>    /usr/bin/php5 -c /home/123456/etc/php.ini -f =
/home/123456/data/auto_reminder.php
>=20
> The "pipe" (|) in unix (and I assume this is unix) means to pipe the =
output
> of php5 -c config to the command "-f /home...php". Which (-f) isn't a =
command.
>=20
> The "semicolon" (;) in unix means "do this command first; then do this =
command"
> so in your second part it is running =
/home/123456/data/auto_reminder.php -udb123456  after it runs php5.
>=20
> Usually php5 -c php.ini will run PHP in interactive mode, and sits and
> waits for input. When run from cron, there is no input, so it dies, =
unable
> to pipe the output (there is none) or just run the next command.
>=20
> So -- lose the pipe, lose the semicolon, just run the command above in =
cron
> (and on the command line) and it should "just work."
>=20
> Beckman
>=20
>=20


Hey thanks Peter for clearing that up. Yes, I was taking the pipe and =
semicolon literally.
I have since found this out on my own that my original code works. It is =
as Richard and Bert had said.
My cron runs under the server admin user and so I have to contact my =
client to find out what that password is or change it.

Much thanks to everyone for your time and responses with my issue. You =
guys are invaluable!

Best,

Karl DeSaulniers
Design Drumm
http://designdrumm.com=

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