bubble sort

John,
 Your swap() is call by value i.e. it makes a copy of the value, thus it
will not affect the arguments in the routine which called it;- I would
propose you to make your
swap() call by reference i.e.calling program passes 'pointers' to the values
to be changed-
n.b.1)swap returns two values, the new values of its arguments.
2)there is a strong relationship between 'pointers' and arrays, so we can
treat them simultaneously.

swap(&a, &b)
int *pa, *pb;
{
     int t;
    t = *pa;
    *pa = *pb;
    *py = t;
}

Bill



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