RE: writing 6 items in one line.

If you do NOT want to go to a new line after each number is output, just
remove the newline characters (\n) in your printf statements and add a space
instead.
Then, add a condition at the bottom of each loop. For example, (double-check
this code, I am writing off the top of my head and have not checked it
myself)

if !(i%3) printf("\n");

What you have done:
For each loop, you have printed a pair of numbers, a and b.
If the loop index, i, is divisible by 3, there is no remainder and the
newline character is printed; otherwise, the next pair of numbers is printed
on the same line.

Hope this helps. (Any reason you are using old-style, C, code rather than
C++ code?)

David Binner
[email protected]

 -----Original Message-----
From: Ronen Kfir [mailto:[email protected]]
Sent: Tuesday, April 13, 2004 1:02 PM
To: [email protected]
Subject: [cppug] writing 6 items in one line.
Importance: High



  Hi,
  I have this code:


  #include <stdio.h>
  void main()
  {
    int    i,n=40;
    float a=0,b=1;
    for (i=1;i<=n;i++)
    {
      printf("%.0f\n",a);
      printf("%.0f\n",b);
      a+=b;
      b+=a;
    }

    getch();
  }

  It present Fibonacci serial of 40 elements. Now I need to divide it to
  groups of 6 in each row.

  Please help me do it.

  Cheers.



  R o n e n   K f i r
  System Administrator
  CIT div. Tel Aviv University
  Israel
  Tel: 972-3-6407416
  Fax: 972-3-6405158
  cellular: 972-55-405910
  E-mail: [email protected]






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