Re: Strange processing!!

Hi Viorel,
Look at Anuj's problem again: In one situation he is initializing b, in 
the other the
same expression is used to change an already initialized b. Both use the 
expression

++a + ++a + ++a
which with a starting at 5 should equal 6 + 7 + 8...so why in the second 
example
is b set to 54? (Anuj you show the outputs as :-21 and :-54 are yours being
printed out as negative numbers?)

Just a sec, lemme write a short program myself and see if I have the 
same problem as
Anuj...


===================
void first(void) {

int a = 5, b= ++a + ++a + ++a;

printf("first %d \n",b);
}

void second(void) {
int a = 5, b=0;

b = ++a + ++a + ++a;
printf("second %d \n",b);
}


int main (void) {

first();
second();

return 0;
}
===================

When compiled and run I get:

first 22
second 22

in both gcc under linux (slackware 3.6) and windows 98 (Microsoft visual 
c/c++ v6.0)
well at least I get the same number.. 22?




Viorel ANUSCA wrote:
> Hi Anuj,
>
> that it is beaucause:
>
>
> –++n increments n before its value is used
>
>
>
> and you have: b = x1+x2+x3 = 6+7+8 = 21
>
> Best,
> Viorel
>
>
> anuj gupta <[email protected]> a écrit :
> Hi All,
> This is Anuj,an MCA std from India.
> I tried the following 2 progs, both resulted in
> different outputs. But i don't understand the REASON
> behind them.
>
> 1.
> int a=5, b = ++a + ++a + ++a;
> printf("%d",b);
> OUTPUT :- 21
>
> 2.
> int a=5, b;
> b = ++a + ++a + ++a;
> printf("%d",b);
> OUTPUT :- 54
>
> Even if i use Macro expansion instead of writing the
> whole expression, even then the result is same.
> If anyone out there can help me out it'll be a big
> help.Thank you.
>
>
>
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