Re: Strange processing!!

>
> Message: 2
>    Date: Fri, 17 Mar 2006 14:26:26 +0000 (GMT)
>    From: anuj gupta <[email protected]>
> Subject: Re: Strange processing!!
>
> Hello Milind,
> First of all i want to tell you that my name is Anuj,
> not Anju...
> Well, thanks for giving the reason behind the value
> 22.
> Another point is that which statement exactly did you
> run on VC++ :
> int b= ++a + ++a + ++a;
> OR
> int b;
> b=++a + ++a + ++a;
>
> In TurboC++, the 2nd case produces the output 24,
> while the first gives 21 (8+7+6).
> But the reason behind 22 is still not very clear,
it gets better and better: i tried this on a mac (ie gcc 33.whatever) :
#include <iostream>

int main (int argc, char * const argv[]) {
   int a1 = 5;
   int a2 = 5;
   int a3 = 5;
   int b1 = (((++a1) + (++a1)) + (++a1));
   std::cout << "int b1 = (((++a1) + (++a1)) + (++a1)); gives " << b1  
<< " and a1 = " << a1 << std::endl;
   int b2 = ((++a2) + (++a2));
   std::cout << "int b2 = ((++a2) + (++a2)); gives " << b2 << " and  
a2 = " << a2 << std::endl;
   int b3 = (++a3) ;
   std::cout << "int b3 = (++a3); gives " << b3 << " and a3 = " << a3  
<< std::endl;
			
   return 0;
}

and received this for my trouble:

int b1 = (((++a1) + (++a1)) + (++a1)); gives 22 and a1 = 8
int b2 = ((++a2) + (++a2)); gives 14 and a2 = 7
int b3 = (++a3); gives 6 and a3 = 6

So, by all appearances there is need for a explaanation for a summand  
of 1 for b1 and b2.
And there is a perfectly sensible b3 that behaves as expected.

Insights, anybody?

mats

> i
> mean why does it calculate the sum for two values
> only?
>
>   Can it be like an overloaded + operator ->
> Calculates the sum of 2 values and adds it to the
> third value.
>
> Another major doubt is that afterall why does it
> processes the 2 statements differently in Turbo?
>
> Anyways, thanks for showing interest to all of you
> folks.
> Take care-
> Anuj.
>
>
>
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