Re: C++ Function With Default Arguments?

Hi Lluís,

Yes, it works.  The error message is a bit misleading.

Thanks!

On Thu, Sep 23, 2021 at 2:03 PM Lluís Alemany Puig <
[email protected]> wrote:

> You could try by adding
>
> %include stdint.i
>
> in the appropriate location in your *.i file.
>
> I didn't try this myself, but that's what I usually do when I use uint32_t,
> int32_t, irrespective of default parameters.
>
> Cheers,
>
> L
> On 23/9/21 5:30, H C wrote:
>
> Hi,
>
> I have the following C++ function in `say.hpp`:
>
>     #include <iostream>
>
>
>     void say(const char* text, const uint32_t x = 16, const uint32_t y =
> 24, const int32_t z = -1) {
>     std::cout << text << std::endl;
>     }
>
>
> Here is my `say.i`:
>
>     %module say
>     %{
>     #include "say.hpp"
>     %}
>
>     %include "say.hpp"
>
> Then, I built the shared library:
>
>     $ swig -python -c++ -I/usr/include say.i
>     $ g++ -fPIC -c say_wrap.cxx
> -I/opt/rh/rh-python38/root/usr/include/python3.8
>     $ g++ -shared say_wrap.o -o _say.so
>
> Then, I tried to call it:
>
>     >>> import say
>     >>> say.say("hello")
>     Traceback (most recent call last):
>       File "<stdin>", line 1, in <module>
>       File "/home/hc/test/cpp/say.py", line 66, in say
>         return _say.say(text, x, y, z)
>     TypeError: Wrong number or type of arguments for overloaded function
> 'say'.
>       Possible C/C++ prototypes are:
>         say(char const *,uint32_t const,uint32_t const,int32_t const)
>         say(char const *,uint32_t const,uint32_t const)
>         say(char const *,uint32_t const)
>         say(char const *)
>
>     >>>
>
> It seems something is wrong with having default values for the function
> parameters as once I remove them, it works.
>
> I searched the mailing list, it seems there was a similar issue back in
> 2015:
>
> https://sourceforge.net/p/swig/mailman/swig-user/thread/9693B382-97FB-41F2-BD0E-D5C009BA087D%40arlut.utexas.edu/#msg33340062
>
> Is it the same bug?
>
> Thanks!
>
>
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