Re: using variant_dir but strip out the variant_dir from source files

Normally SCons will have the compiler output the target data into the Variant directory. In certain cases, the compiler doesn't allow control of where the output happens. SCons has a feature to change the current directory for you. However, this feature as it is, breaks the -j based builds. I work around this in my builds by changing the action to "cd  <variant directory> ; <compiler command>". This seems to solve the issue of compilers messing up stuff on disk for me at least.
-Jason
________________________________
From: Scons-users <[email protected]> on behalf of Hua Yanghao <[email protected]>
Sent: Wednesday, October 17, 2018 2:55 PM
To: SCons users mailing list
Subject: [Scons-users] using variant_dir but strip out the variant_dir from source files

Dear Scons User,
I am having maybe an odd request. The background is there are some
compilers out there produces all kinds of output in your current
directory which you do not have control. I wanted to combine the
variant_dir feature plus the chdir kw arguments to builders, to be
able to invoke those compilers directly inside the variant_dir. And I
still want to keep the source duplication in the variant_dir as it
will be a snapshot of only the used files for a particular built out
of thousands of irrelevant files. As a side effect now the source
files are all prefixed with the variant_dir which becomes "invalid"
because the compiler is already invoked in the variant_dir instead of
the top level directory.

Is there a way (e.g. a special env variable) already that when I write
my builders instead of "$COMPILER $SOURCE", I can use something like
"$COMPILER $ORIGINAL_SOURCE"? Or do I have to wrap around the
$COMPILER with another command such that I can do things like
"$COMPILER_WRAPPED $VARIANT_DIR $SOURCE"? I know the second one
definitely can work but wondering if there are better ways already in
scons.

Best Regards,
Yanghao
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