Re: executing while loop and simultaneously redirecting to new page on form submission

Hi,

this is a typical use case for multi-threaded programming. 

Your web interface just  sets a variable (protected by a mutex), and a 
background  thread does the LED output.

Björn

Am Donnerstag, 13. Oktober 2016 07:44:03 UTC+2 schrieb Peter Tsapatsaris:
>
> Hello everyone,
>
> I've been using cherrypy on a Raspberry Pi to run a web controllable LED 
> matrix.  I've run into a bit of a wall.  Short version of question: Is it 
> possible to send the user to a new webpage in a function WITHOUT returning 
> or breaking?  I am trying to execute code in a block below the redirect. 
>
> Long version:
>
> The LED control code executes on a while loop after receiving input from 
> an an HTML form like the following:
>
>     <form name="myform" class="rounded" action="ledDisplay" method="GET" 
> onsubmit="archive.html">         
>         <input type="text" class="box" name="message" maxlength="1000" 
> placeholder="enter your message" />
>         <input type="submit">
>     </form>
>
> The ledDisplay function executes the while loop with the message from the 
> form.  My problem is this--after submission, I would like to redirect the 
> user to a new webpage (e..g, "thanks.html").  However, when I redirect it 
> either executes BEFORE the while loop, thus preventing the LED from 
> running, or executes AFTER the while loop, i.e., never.  
>
> Does anyone know if there is a way to get CherryPy to send the user to a 
> new webpage and then continue to execute a code block?  Here is a skeleton 
> of the code I'm working with:
>
> class myApp:
>
> def index(self):
>
> return open('index.html')
>
> index.exposed = True
>
> def ledDisplay(self, message):
>
>
> if message:
>
> raise cherrypy.HTTPRedirect("thanks.html") /* This prevents the loop from 
> executing.  Any way to open the page and still execute the loop*/
>
>  
>
> while True:
>
>                                //Execute LED code on loop.
> Apologies if I'm being obtuse - I am new to programming. 
>

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