Re: argsparse: allowing --version without mandatory options

Anders Munch <[email protected]>
Newsgroups gmane.comp.python.general
Message-ID <PAXPR05MB96639C80A8D9C1ACC0966519B4F8A@PAXPR05MB9663.eurprd05.prod.outlook.com>
From: [email protected] <[email protected]>:
> Don't take this the wrong way, but what, exactly, is a mandatory option?

It's a named argument.
Positional arguments intermixed with options can get confusing. When you see 
     aprogram.py --a --b c --d --e
is 'c' the value for --b, or is it a positional argument? Hard to tell.
Using options syntax for everything makes it clearer, because everything has a name:
     aprogram.py --a --b --c c --d --e

Whether an argument is named and whether it's optional are orthogonal traits.
Positional arguments can be optional as well, and named arguments ("options") can be mandatory.

regards, Anders
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