Re: Rock Paper Scissors Code Bug?

On 08/12/2025 21:18, Thomas Passin wrote:
> On 12/8/2025 2:49 PM, John Smith via Python-list wrote:
>> Thanks for the tip. I'll do that here and in future games.
>
> In addition to using constants to parameterize the strings, the whole 
> game can be made simpler and easier to change when you realize that 
> the if/else block has a regular construction.  Here's a sketch of one 
> way to take advantage of this structure (untested).  You should be 
> able to fill in the elided code. Use lower case to check the input so 
> a mistake in capitalization doesn't reject the input.  That's a simple 
> courtesy to the user.
>
> import random #Allows for a random input.
>
> ROCK = 'rock'
> PAPER = 'paper'
> SCISSORS = 'scissors'
> TIE = 'Tie'
> ULOSE = 'You Lose'
> UWIN = 'You Win'
>
> GAME = {
>     (ROCK, ROCK): TIE,
>     (ROCK, PAPER): ULOSE,
>     # ...
> }
>
> OPTIONS = (ROCK, PAPER, SCISSORS)
> PROMPT = (f'Welcome to the {ROCK}, {PAPER}, {SCISSORS} game. ' +
>         'Choose one of the three')
>
> # skipping some code
>     player_choice = input(PROMPT)
>     player_choice = player_choice.lower()
>     if player_choice not in OPTIONS:
>         print(f'{player_choice} is not an allowed input')
>         continue
>     result = GAME[(player_choice, choice)]
>     print(result)
>     # ...
>
There's another way of determining who won.

Give each of the choices a value, such as:

     OPTION_VALUES = {ROCK: 0, PAPER: 1, SCISSORS: 2}

Look at the difference between the values of what the bot chose and what 
the player chose.

There are 5 possible differences, from -2 to +2.

 From that difference you can determine who won or whether it's a tie.
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