=?eucgb2312_cn?b?UmU6IFJlZ2FyZGluZyBucGFycmF5IHJlc2hhcGUo?= =?eucgb2312_cn?b?KSBhbmQgcmVmY291bnQgKMzawfUp?=
Stefano Miccoli via NumPy-Discussion <[email protected]>
| Newsgroups | gmane.comp.python.numeric.general |
|---|---|
| Message-ID | <[email protected]> |
On 30 Sep 2025, at 18:00, [email protected] wrote: It seems that B2's ref of A2 is stolen by this assignment out = B2. And In A3 , B3 case, we deleteout first and it seems that the ref in out is returned back to B3. I'm not sure if this is the intended behavior and I cannot find any material or documentation about this. Any thoughts or suggestions would be helpful! Teng Liu The statement `B2 = A2.reshape((10, 10))` increments the refcount of A2 in an indirect way: it is B2.base that holds the reference to A2. In fact, `B2.base is A2` is True. Therefore, incrementing the refcount of B2 (with `out2 = B2`) will not increment also the refcount of A2. Hope this helps, Stefano _______________________________________________ NumPy-Discussion mailing list -- [email protected] To unsubscribe send an email to [email protected] https://mail.python.org/mailman3//lists/numpy-discussion.python.org Member address: [email protected]