Re: Can I register a function (not a class) ?

It was meant for a debug server/client situation, like:

def deb(any, debvars=[]):
nowt = '\n++++ ' + getnow()
# get name of function that called me
name = ', function : ' + inspect.stack()[1][3]
vars = [nowt + name]
        etc

I do not think this will work form a class.
It sort of worked with sockets, but too much trouble, so I thought maybe
Pyro could be used here.

Richard

Richard



2013/10/18 Irmen de Jong <[email protected]>

> On 18-10-2013 23:03, Richard van Bemmelen wrote:
> > Since in Python everything is an object, I thought this would be
> possible to but it does
> > not work.
> >
> > Richard
> >
>
> Not sure what you're trying to accomplish, but this (silly) example does
> work:
>
> import Pyro4
>
> def func(arg):
>    return arg*arg
>
> func.foo = lambda x: x+x
>
> Pyro4.Daemon.serveSimple({
>     func: "thing"
> }, ns=False)
>
>
>
> Notice though that because you expose the function object itself through
> Pyro, any
> remote method call performed on the proxy for it will translate in a
> "method" call on
> the fuction object, rather than a direct invocation of the function itself.
>
> You cannot do a direct call on the proxy such as: proxy(55), because the
> Pyro proxy is
> not a callable right now. I guess that could be added in a future version.
>
>
> In the meantime, make your function a member of a class and register the
> class with
> Pyro. Then call your function as a remote method on the proxy for it.
>
> Irmen
>
>
>
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