Re: Pyro4 ver 4.35 hmac key config not symmetric

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Thanks for the response.  I have updated the code to the following:
daemon =3D Pyro4.Daemon(*IP*)
key =3D "test1"
daemon._pyroHmacKey =3D key
nameServer =3D Pyro4.locateNS(*IP*)
nameServer._pyroHmacKey =3D key
uri =3D daemon.register(*self*)
nameServer.register(name, uri)

I am still getting the HMAC key not symmetric error at the
nameServer.register line.  Any ideas?

Thanks,
Katelyn

On Sat, Apr 11, 2015 at 3:39 PM, Irmen de Jong <[email protected]> wrote:

> On 10-4-2015 22:23, Katelyn Thode wrote:
> > Hello,
> >
>
> Hello Katelyn
>
>
> > I am having an issue when attempting to set up the hmac key for Pyro4 i=
n
> code.  The
> > versions being used are as follows:
> > Pyro 4: 4.35
> > Python: 2.7.9
> >
> > The error message is:
> > Pyro4.errors.SecurityError: hmac key config not symmetric
> >
> > The code that is being used is below:
> > daemon =3D Pyro4.Daemon(/IP/)
> > key =3D str(/self/.get_hmac_key())
> > daemon._pyroHmacKey =3D key
> > nameServer =3D Pyro4.locateNS(/IP/)
> > nameServer._pyroHmacKey =3D key
> > uri =3D daemon.register(/self/)
> > nameServer.register(name, uri)
> >
> > get_hmac_key():
> >      key =3D =E2=80=9Ctest1"
> >      msg =3D =E2=80=9Ctest2"
> >      hmac_obj =3D hmac.new(key, msg, hashlib.sha256)
> >      hmac_key =3D hmac_obj.hexdigest()
> >      returnhmac_key
> >
> > The line that the error is thrown at is nameServer.register(name, uri).
> Please advise
> > on what I am doing incorrectly.
> >
>
> I think the problem is in the way you're providing the hmac key to Pyro.
> You should not be encoding it / hmac'ing it yourself; just provide the ke=
y
> to Pyro
> directly. If I understand your code correctly, your key is "test1".
> I assume you have started your nameserver with the "-k test1" argument?
> So just set _pyroHmacKey=3D"test1".
>
> See
>
> https://pythonhosted.org/Pyro4/security.html#preventing-arbitrary-connect=
ions-hmac-signature
>
>
> > Thanks,
> > Katelyn
>
> Hope the above helps you to get your code working. Let us know!
>
>
> Cheers
> Irmen
>
>
>
> -------------------------------------------------------------------------=
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<div dir=3D"ltr">Thanks for the response.=C2=A0 I have updated the code to =
the following:<div><div style=3D"font-size:12.8000001907349px"><span style=
=3D"font-stretch:normal;font-size:10px;font-family:Consolas">daemon =3D Pyr=
o4.Daemon(</span><span style=3D"font-size:10px;font-family:Consolas"><i>IP<=
/i>)</span></div><div style=3D"font-size:12.8000001907349px"><span style=3D=
"font-size:10px"><span style=3D"font-family:Consolas">key =3D &quot;test1&q=
uot;</span></span></div><div style=3D"font-size:12.8000001907349px"><span s=
tyle=3D"font-size:10px"><span style=3D"font-family:Consolas">daemon._pyroHm=
acKey =3D key</span></span></div><div style=3D"font-size:12.8000001907349px=
"><span style=3D"font-size:10px"><span style=3D"font-family:Consolas">nameS=
erver =3D Pyro4.locateNS(<i>IP</i>)</span></span></div><div style=3D"font-s=
ize:12.8000001907349px"><span style=3D"font-size:10px"><span style=3D"font-=
family:Consolas">nameServer._pyroHmacKey =3D key</span></span></div><div st=
yle=3D"font-size:12.8000001907349px"><span style=3D"font-size:10px"><span s=
tyle=3D"font-family:Consolas">uri =3D daemon.register(<i>self</i>)</span></=
span></div><div style=3D"font-size:12.8000001907349px"><span style=3D"font-=
family:Consolas"><span style=3D"font-size:10px">nameServer.register(name, u=
ri)</span></span></div></div><div style=3D"font-size:12.8000001907349px"><s=
pan style=3D"font-family:Consolas"><span style=3D"font-size:10px"><br></spa=
n></span></div><div>I am still getting the HMAC key not symmetric error at =
the nameServer.register line.=C2=A0 Any ideas?<br></div><div><br></div><div=
>Thanks,</div><div>Katelyn</div></div><div class=3D"gmail_extra"><br><div c=
lass=3D"gmail_quote">On Sat, Apr 11, 2015 at 3:39 PM, Irmen de Jong <span d=
ir=3D"ltr">&lt;<a href=3D"mailto:[email protected]" target=3D"_blank">irm=
[email protected]</a>&gt;</span> wrote:<br><blockquote class=3D"gmail_quote"=
 style=3D"margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex">On=
 10-4-2015 22:23, Katelyn Thode wrote:<br>
&gt; Hello,<br>
&gt;<br>
<br>
Hello Katelyn<br>
<span class=3D""><br>
<br>
&gt; I am having an issue when attempting to set up the hmac key for Pyro4 =
in code.=C2=A0 The<br>
&gt; versions being used are as follows:<br>
&gt; Pyro 4: 4.35<br>
&gt; Python: 2.7.9<br>
&gt;<br>
&gt; The error message is:<br>
&gt; Pyro4.errors.SecurityError: hmac key config not symmetric<br>
&gt;<br>
&gt; The code that is being used is below:<br>
</span>&gt; daemon =3D Pyro4.Daemon(/IP/)<br>
&gt; key =3D str(/self/.get_hmac_key())<br>
&gt; daemon._pyroHmacKey =3D key<br>
&gt; nameServer =3D Pyro4.locateNS(/IP/)<br>
&gt; nameServer._pyroHmacKey =3D key<br>
&gt; uri =3D daemon.register(/self/)<br>
<span class=3D"">&gt; nameServer.register(name, uri)<br>
&gt;<br>
&gt; get_hmac_key():<br>
&gt;=C2=A0 =C2=A0 =C2=A0 key =3D =E2=80=9Ctest1&quot;<br>
&gt;=C2=A0 =C2=A0 =C2=A0 msg =3D =E2=80=9Ctest2&quot;<br>
&gt;=C2=A0 =C2=A0 =C2=A0 hmac_obj =3D hmac.new(key, msg, hashlib.sha256)<br=
>
&gt;=C2=A0 =C2=A0 =C2=A0 hmac_key =3D hmac_obj.hexdigest()<br>
&gt;=C2=A0 =C2=A0 =C2=A0 returnhmac_key<br>
&gt;<br>
&gt; The line that the error is thrown at is nameServer.register(name, uri)=
.=C2=A0 Please advise<br>
&gt; on what I am doing incorrectly.<br>
&gt;<br>
<br>
</span>I think the problem is in the way you&#39;re providing the hmac key =
to Pyro.<br>
You should not be encoding it / hmac&#39;ing it yourself; just provide the =
key to Pyro<br>
directly. If I understand your code correctly, your key is &quot;test1&quot=
;.<br>
I assume you have started your nameserver with the &quot;-k test1&quot; arg=
ument?<br>
So just set _pyroHmacKey=3D&quot;test1&quot;.<br>
<br>
See<br>
<a href=3D"https://pythonhosted.org/Pyro4/security.html#preventing-arbitrar=
y-connections-hmac-signature" target=3D"_blank">https://pythonhosted.org/Py=
ro4/security.html#preventing-arbitrary-connections-hmac-signature</a><br>
<br>
<br>
&gt; Thanks,<br>
&gt; Katelyn<br>
<br>
Hope the above helps you to get your code working. Let us know!<br>
<br>
<br>
Cheers<br>
Irmen<br>
<br>
<br>
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Develop your own process in accordance with the BPMN 2 standard
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