Re: approach used in special function iti0k0
Albert Steppi <[email protected]> Sun, 5 Jun 2022 10:30:45 -0400
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--===============5547905074925740877== Content-Type: multipart/alternative; boundary="000000000000947af205e0b435e0" --000000000000947af205e0b435e0 Content-Type: text/plain; charset="UTF-8" Content-Transfer-Encoding: quoted-printable Hi Mark, The relevant reference is *Computation of Special Functions, Shanjie Zhang and Jianming Jin, 1996, John Wiley & Sons, Inc.* See section 6.2., pages 207-212 of the original edition. It seems like it would be a good idea to add this reference to the docstring. Best, Albert On Sun, Jun 5, 2022 at 10:08 AM Mark Bakker <[email protected]> wrote: > I am searching for the approach/algorithm used to compute the special fun= ction iti0k0. The docs only state that the integrals \int_0^x I_0(t) dt and= \int_0^x K_0(t) dt are computed, but I couldn't find a link/reference to t= he algorithm/approach used to compute these. > > Even iti0k0?? doesn't help. > > > Anybody know? > > > Thanks, > > > Mark > > _______________________________________________ > SciPy-User mailing list -- [email protected] > To unsubscribe send an email to [email protected] > https://mail.python.org/mailman3/lists/scipy-user.python.org/ > Member address: [email protected] > --000000000000947af205e0b435e0 Content-Type: text/html; charset="UTF-8" Content-Transfer-Encoding: quoted-printable <div dir=3D"ltr"><div>Hi Mark,</div><div><br></div><div>The relevant refere= nce is <i><span class=3D"gmail-pl-c">Computation of Special Functions, <spa= n class=3D"gmail-pl-c"> Shanjie Zhang and Jianming Jin, </span>1996, John W= iley & Sons, Inc.</span></i></div><div><span class=3D"gmail-pl-c">See s= ection 6.2., pages 207-212 of the original edition. It seems like it would = be a good idea to add this reference to the</span></div><div><span class=3D= "gmail-pl-c">docstring.</span></div><div><span class=3D"gmail-pl-c"><br></s= pan></div><div><span class=3D"gmail-pl-c">Best,</span></div><div><span clas= s=3D"gmail-pl-c">Albert<br></span></div><div><i><span class=3D"gmail-pl-c">= </span></i></div><div><table class=3D"gmail-highlight gmail-tab-size gmail-= js-file-line-container gmail-js-code-nav-container gmail-js-tagsearch-file"= ><tbody><tr><td id=3D"gmail-LC6" class=3D"gmail-blob-code gmail-blob-code-i= nner gmail-js-file-line"><span class=3D"gmail-pl-c"><br><br></span></td> </tr> <tr> </tr></tbody></table></div></div><br><div class=3D"gmail_quote"><= div dir=3D"ltr" class=3D"gmail_attr">On Sun, Jun 5, 2022 at 10:08 AM Mark B= akker <<a href=3D"mailto:[email protected]">[email protected]</a>> wr= ote:<br></div><blockquote class=3D"gmail_quote" style=3D"margin:0px 0px 0px= 0.8ex;border-left:1px solid rgb(204,204,204);padding-left:1ex"><div dir=3D= "ltr"><pre style=3D"box-sizing:unset;border:medium none;margin-top:0px;marg= in-bottom:0px;padding:0px;overflow:auto;word-break:break-all;white-space:pr= e-wrap">I am searching for the approach/algorithm used to compute the speci= al function <span style=3D"font-family:Arial,Helvetica,sans-serif">iti0k0. = The docs only state that the integrals </span><span style=3D"font-family:Ar= ial,Helvetica,sans-serif">\int_0^x I_0(t) dt and </span><span style=3D"font= -family:Arial,Helvetica,sans-serif">\int_0^x K_0(t) dt are computed, but I = couldn't find a link/reference to the algorithm/approach used to comput= e these.=C2=A0</span></pre><pre style=3D"box-sizing:unset;border:medium non= e;margin-top:0px;margin-bottom:0px;padding:0px;overflow:auto;word-break:bre= ak-all;white-space:pre-wrap"><span style=3D"font-family:Arial,Helvetica,san= s-serif">Even </span><span style=3D"font-family:Arial,Helvetica,sans-serif"= >iti0k0?? doesn't help.</span></pre><pre style=3D"box-sizing:unset;bord= er:medium none;margin-top:0px;margin-bottom:0px;padding:0px;overflow:auto;w= ord-break:break-all;white-space:pre-wrap"><span style=3D"font-family:Arial,= Helvetica,sans-serif"><br></span></pre><pre style=3D"box-sizing:unset;borde= r:medium none;margin-top:0px;margin-bottom:0px;padding:0px;overflow:auto;wo= rd-break:break-all;white-space:pre-wrap"><span style=3D"font-family:Arial,H= elvetica,sans-serif">Anybody know?</span></pre><pre style=3D"box-sizing:uns= et;border:medium none;margin-top:0px;margin-bottom:0px;padding:0px;overflow= :auto;word-break:break-all;white-space:pre-wrap"><span style=3D"font-family= :Arial,Helvetica,sans-serif"><br></span></pre><pre style=3D"box-sizing:unse= t;border:medium none;margin-top:0px;margin-bottom:0px;padding:0px;overflow:= auto;word-break:break-all;white-space:pre-wrap"><span style=3D"font-family:= Arial,Helvetica,sans-serif">Thanks,</span></pre><pre style=3D"box-sizing:un= set;border:medium none;margin-top:0px;margin-bottom:0px;padding:0px;overflo= w:auto;word-break:break-all;white-space:pre-wrap"><span style=3D"font-famil= y:Arial,Helvetica,sans-serif"><br></span></pre><pre style=3D"box-sizing:uns= et;border:medium none;margin-top:0px;margin-bottom:0px;padding:0px;overflow= :auto;word-break:break-all;white-space:pre-wrap"><span style=3D"font-family= :Arial,Helvetica,sans-serif">Mark</span></pre></div> _______________________________________________<br> SciPy-User mailing list -- <a href=3D"mailto:[email protected]" target= =3D"_blank">[email protected]</a><br> To unsubscribe send an email to <a href=3D"mailto:[email protected]= rg" target=3D"_blank">[email protected]</a><br> <a href=3D"https://mail.python.org/mailman3/lists/scipy-user.python.org/" r= el=3D"noreferrer" target=3D"_blank">https://mail.python.org/mailman3/lists/= scipy-user.python.org/</a><br> Member address: <a href=3D"mailto:[email protected]" target=3D"_blank= ">[email protected]</a><br> </blockquote></div> --000000000000947af205e0b435e0-- --===============5547905074925740877== Content-Type: text/plain; charset="us-ascii" MIME-Version: 1.0 Content-Transfer-Encoding: 7bit Content-Disposition: inline _______________________________________________ SciPy-User mailing list -- [email protected] To unsubscribe send an email to [email protected] https://mail.python.org/mailman3/lists/scipy-user.python.org/ Member address: [email protected] --===============5547905074925740877==--