Re: im having problems and need help

Misti Hamon <[email protected]>
Newsgroups gmane.comp.python.tutor
Message-ID <CAEnOb6RQxdvTyd8jVf-m0dSJ9A9048mqEvMaQ_ZbMTfSYkN2Hw@mail.gmail.com>
Your math is incorrect. And as a result, you are running the whole code
wrong.

To start you out, the % is the modulo operator. Modulo returns the
remainder portion of division, so, 5 % 3 would return 2 (3 goes into 5 1
time, with 2 remaining), 5 % 2 would return 1 (2 goes into 5 2 times with
remainder 1).

On Wed, Sep 20, 2023, 00:05 Robert Towne <[email protected]> wrote:

> Im having problems understanding this. Im running the while loop like it
> says; and it doesnt complete the loop.
> My question is, is it the formula thats wrong or my math. The % sign means
> to square the number?
> since i the to the second power is 64. Then it should return false. IDK
> what I am doing wrong, if you could
> help me understand where I am going wrong i would appreciate it thank you.
>
> def is_power_of_two(number):
> # This while loop checks if the "number" can be divided by two
> # without leaving a remainder. How can you change the while loop to
> # avoid a Python ZeroDivisionError?
> while number % 2 == 0:
> number = number / 2
> # If after dividing by 2 "number" equals 1, then "number" is a power
> # of 2.
> if number == 1:
> return True
> return False
>
> # Calls to the function
> print(is_power_of_two(0)) # Should be False
> print(is_power_of_two(1)) # Should be True
> print(is_power_of_two(8)) # Should be True
> print(is_power_of_two(9)) # Should be False
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