Re: matx3.py

On 12/27/23 15:34, Ethan Rosenberg wrote:
> Tutor -

> mat = [[1],[2],[3]],[[4],[5],[6]],[[7],[8],[9]]

> I receive an error that  mat[k] = i*j is a tuple??

believe it or not your initialization of mat sets it to a tuple - a 
tuple consisting of three lists, each consisting of three lists 
containing a single element. The interactive interpreter will try to 
show it as a tuple by adding parens, but it's not the parens that make 
it a tuple: comma-separated elements that aren't otherwise enclosed in 
known container syntax (e.g. list, set, dict) makes it a tuple.

 >>> mat = [[1],[2],[3]],[[4],[5],[6]],[[7],[8],[9]]
 >>> type(mat)
<class 'tuple'>
 >>> mat
([[1], [2], [3]], [[4], [5], [6]], [[7], [8], [9]])
 >>>

It's doubtful this is what you want. Nor your later code where you nest 
loops three deep and will end up repeating stuff you don't expect. A 
print statement here will show you what's happening:

....
         for k in range(0,8):
             print(f"Setting mat[{k}] to {i * j}")
             mat[k] = i*j

Giving:
Setting mat[0] to 0
Setting mat[1] to 0
Setting mat[2] to 0
Setting mat[3] to 0
Setting mat[4] to 0
Setting mat[5] to 0
Setting mat[6] to 0
Setting mat[7] to 0
Setting mat[0] to 0
Setting mat[1] to 0
Setting mat[2] to 0
Setting mat[3] to 0
Setting mat[4] to 0
Setting mat[5] to 0
Setting mat[6] to 0
Setting mat[7] to 0
Setting mat[0] to 0
Setting mat[1] to 0
Setting mat[2] to 0
Setting mat[3] to 0
Setting mat[4] to 0
Setting mat[5] to 0
Setting mat[6] to 0
Setting mat[7] to 0
Setting mat[0] to 1
Setting mat[1] to 1
Setting mat[2] to 1
Setting mat[3] to 1
Setting mat[4] to 1
Setting mat[5] to 1
Setting mat[6] to 1
Setting mat[7] to 1

Notice the repeat setting of mat[0] through mat[7] (and no mat[8]), to 
the wrong values, and think for a while until you understand why it's 
working this way.

As I expect people have pointed out to you (sorry haven't followed the 
whole thread), Python itself has no concept of a two-dimensional matrix. 
If you want that, use the (external, and very popular) numpy module. 
You can fake it with a list (single-dimensional array), as you're trying 
to do.

If I've twigged what you want, something like this can set it up, trying 
to avoid zero values - again, it's kind of a guess that this is what 
you're after:

mat = []
for i in range(1, 4):
     for j in range(1, 4):
         mat.append(i * j)

You can write that whole thing as a "list comprehension", which is a bit 
more advanced:

mat = [i * j for i in range(1, 4) for j in range(1, 4)]

And to print it out so it "looks" like a matrix you can get a little tricky:

for idx, elem in enumerate(mat, start=1):
     print(elem, end=" " if idx % 3 else "\n")

That causes each third element to emit a line break after it's printed, 
the other two will emit a space. The print function syntax shown is 
slightly advanced, don't worry if you haven't seen that yet, you can 
come back to that later.


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