Re: P2 protocol question

Well, if you're dealing with BigEndian vs LittleEndian, all that's
happening is that the bytes come in a different order for each number.
Thankfully, these numbers are only two bytes long, so it's easy.

Easy C one-liner:

swapped = (num>>8) | (num<<8)


where 'num' is your input int and 'swapped' is your output. It's simply
putting the last 8 bits before the first 8. Incidentally, that brings your
values in that list to:

90
1023
995
832
690
587

which are all under 1024. Basically, you're being sent a 12-bit number, but
it's enclosed in a 16-bit shell. The reason it's higher than 1023 is
because you haven't converted your endianness.

Hope that helps!

On Mon, Dec 10, 2012 at 1:33 AM, Savchenko Dmitry <[email protected]>wrote:

> Hello!
>
> Can you describe values in `uint16_t data[6]` sent in ModEEG package?
> And have I convert these values from BigEndian to LittleEndian?
>
> --
> Best regards, Dmitry Savchenko
>
>
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