Re: electrical problems with Galvanic Skin Response circuit ( GSR SCL )

Steffen <[email protected]>
Newsgroups gmane.comp.science.openeeg.general
Message-ID <[email protected]>
Hi Stefan,


> 1. A high skin resistance gives a low output voltage, a low skin resistance
> value gives a high output voltage.
>
> 2. The above point can be proven by inspection - if skin resistance is
> infinitely high the opamp acts as a simple unity gain amplifier and the
> same 0.5V Vref will be applied to the + and - inputs of the INA, the
> differential voltage is thus zero and the INA's output is zero.
>
> 3. If the skin resistance is 0 ohms, the opamp's gain will be infinitely
> high and it will saturate at it's Vcc.  The gain of the INA should be
> adjusted to then give a FSD value compatible with your ADC's maximum input
> voltage (also FSD).

This is the case for 1. and  2., but for 3. the Output is not 5V, but 4,7V.

> 6. Do not randomly guess resistance values.  Choose a combination of
> resistors, calculate the expected voltages at the opamp and instrumentation
> amplifier's outputs and then verify with a multimeter or scope if the
> measure values correspond with the theoretical values.  First ensure that
> your opamp works as expected and then check correct operation of your INA.

I didn't guess totally randomly, i calculated with an Excel sheet values 
and tried to get an output voltage over the full  scale, but while i 
studied the formulas i came to the conclusion, that it is impossible to 
get a full scale output voltage from 0,5 to 5V if the skin resistance is 
alternating between 800k and 900k however i  choose the combination of 
resistors.
Maybe it is not an error, but willed so from the designer of the 
lightstone as you describe at 9.

> 7. To do point (6) consider the opamp as just a simple non-inverting
> amplifier.  The gain is set by  R24 and SCL.  The "input" voltage is simply
> Vref, which I have fixed in my design at 500mV.

The opamp works fine and the calculations correspond with the 
theoretical values.


> 8. The INA is simply a difference amplifier.  You take the output voltage
> of the opamp, subtract Vref (0.5V) and multiply by the INAs gain.

The INA doesn't work as accepted. I operated the INA standalone with a 
voltage divider made of resistors and the behaviour is always the same.
The output of the INA is  to less.

f.e:

R25=1,47k-->Gain=69

+Input:0,560V
-Input: 0,486V
difference:0,074V

Output Voltage: 2,235V
Gain:30,2
Gain_theoretical:69

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
with increased power supply of 6V:
+Input:0,847V
-Input: 0,566V
difference:0,281V

Output Voltage: 2,79V
Gain:10
Gain_theoretical:69

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
+IN to ground (single-ended)

+Input:0V
-Input: 0,714V
difference:0,714V

Output Voltage: 2,54V
Gain:3
Gain_theoretical:69

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Maybe my INA is defect?
Btw, what does 5VA ISO mean? VA is technically Watt?
Does ISO mean isolated for safety reasons?



>
> 9. Although the skin resistance always tends to be high, the circuit was
> designed to measure down to nearly zero.  This is also what the lightstone
> does.  If you don't like that operation, you would need to shift the INA's
> DC offset by applying a low impedance source, DC offset voltage to pin 5
> (Vref of the INA).

I will test this, when the problems from 8. are solved

Regards Steffen


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