Re: [TYPES] Topology of the type T = T -> T
Martin Escardo <[email protected]>
| Newsgroups | gmane.comp.science.types |
|---|---|
| Organization | University of Birmingham |
| Message-ID | <[email protected]> |
[ The Types Forum, http://lists.seas.upenn.edu/mailman/listinfo/types-list ] On 30/11/14 22:05, Izaak Meckler wrote: > [ The Types Forum, http://lists.seas.upenn.edu/mailman/listinfo/types-list ] > > Hi all, > > Does anyone know any resources describing the topology of the (say, Haskell > 98) type given by > > data T = T (T -> T) > > This is something like the type of untyped lambda calculus programs. The > topology I have in mind is defined as follows. A subset X of T is open set > if there is a Haskell term > > f :: T -> () > > with f x = () for x in A, and f x = undefined otherwise. The topology on T > is the one generated by these open sets (generated in the classical sense, > although I'd be interested also in the case where the unions are required > to be definable functions out of Nat as described by Martin Escardo here > <http://www.cs.bham.ac.uk/%7Emhe/papers/entcs87.pdf>, p. 33). > > It is not hard to show that T has non-trivial topology (for example, there > are open sets separating the two church booleans) and it seems it's not > compact. I'd appreciate any other info people have on this topology. The references Guy gave you should help you to describe the topology more explicitly. Just one comment: the topology is compact, simply because there is a bottom element in the domain. The same is true for the type of integers: it is compact because it has a bottom. What is not true for the type of integers is that the total elements form a compact set (related to the Halting Problem). You could ask whether the total elements of T form a compact set. But we first have to agree what the total elements of T are/should be. Back in 1997 in a domains workshop in Munich, Gordon Plotkin showed that there is no reasonable notion of totality for such a domain, if I remember correctly. But he didn't write this up, as far as I know. Best wishes, Martin