do R1, R2 and RV need to be updated after deleting something?
<[email protected]> Thu, 26 Aug 2021 12:27:23 +0200
| Newsgroups | gmane.comp.search.snowball |
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Hello to all.
I am implementing the stemming algorithm for Italian =
(https://snowballstem.org/algorithms/italian/stemmer.html), and I have a =
doubt:
I have a word, say =E2=80=9Cpraticabilit=C3=A0=E2=80=9D
R1 is =E2=80=9Cicabilit=C3=A0=E2=80=9D
R=E2=80=9D is =E2=80=9Cabilit=C3=A0=E2=80=9D
RV is =E2=80=9Cticabilit=C3=A0=E2=80=9D
(or at least I hope so =F0=9F=98=8A)
In step 1 there is the rule:
it=C3=A0
delete if in R2
if preceded by abil, ic or iv, delete if in R2
And in step 3 there is the rule:
Delete a final a, e, i, o, =C3=A0, =C3=A8, =C3=AC or =C3=B2 if it is in =
RV, and a preceding i if it is in RV=20
In step 1 I delete =E2=80=9Cabilit=C3=A0=E2=80=9D and the word becomes =
=E2=80=9Cpratic=E2=80=9D
=20
I leave RV untouched, and so it is still =
=E2=80=9Cticabilit=C3=A0=E2=80=9D
=20
In step 3 I search for =E2=80=9C=C3=A0=E2=80=9D in RV and I found it as =
last character.
So I think I have to delete 1 character and I delete wrongly =
=E2=80=9Cc=E2=80=9D
=20
I wonder which the correct algorithm is. Maybe I need to delete matches =
from R1, R2, and RV too?
Thanks in advance for your help.
Alfonso
=20
Alfonso Moscato
CIO & COO
Merqurio Holding
Corso Umberto I, 23 - 80138 Napoli
Tel.+39 0815524300=20
Fax.+39 0814201136=20
Linea Verde: +39 800014863=20
=20
Diretto. +39 081 96.336.22=20
Mobile. +39 348 36.79.384
=20
=20
=20
=20
=20
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link=3D"#0563C1" vlink=3D"#954F72" style=3D'word-wrap:break-word'><div =
class=3DWordSection1><p class=3DMsoNormal>Hello to all.<o:p></o:p></p><p =
class=3DMsoNormal>I am implementing the stemming algorithm for Italian =
(<a =
href=3D"https://snowballstem.org/algorithms/italian/stemmer.html">https:/=
/snowballstem.org/algorithms/italian/stemmer.html</a>), and I have a =
doubt:<o:p></o:p></p><p class=3DMsoNormal>I have a word, say =
=E2=80=9Cpraticabilit=C3=A0=E2=80=9D<o:p></o:p></p><p =
class=3DMsoNormal>R1 is =
=E2=80=9Cicabilit=C3=A0=E2=80=9D<o:p></o:p></p><p =
class=3DMsoNormal>R=E2=80=9D is =
=E2=80=9Cabilit=C3=A0=E2=80=9D<o:p></o:p></p><p class=3DMsoNormal>RV is =
=E2=80=9Cticabilit=C3=A0=E2=80=9D<o:p></o:p></p><p class=3DMsoNormal>(or =
at least I hope so <span style=3D'font-family:"Segoe UI =
Emoji",sans-serif'>😊</span>)<o:p></o:p></p><p =
class=3DMsoNormal>In step 1 there is the rule:<o:p></o:p></p><p =
class=3DMsoNormal =
style=3D'margin-left:36.0pt;background:white'><b><i><span lang=3DEN-GB =
style=3D'font-size:10.5pt;font-family:"Helvetica",sans-serif;color:#33333=
3;mso-fareast-language:IT'>it=C3=A0</span></i></b><b><span lang=3DEN-GB =
style=3D'font-size:10.5pt;font-family:"Helvetica",sans-serif;color:#33333=
3;mso-fareast-language:IT'><o:p></o:p></span></b></p><p =
class=3DMsoNormal style=3D'margin-left:36.0pt;background:white'><span =
lang=3DEN-GB =
style=3D'font-size:10.5pt;font-family:"Helvetica",sans-serif;color:red;ms=
o-fareast-language:IT'>delete if =
in <i>R</i>2<o:p></o:p></span></p><p class=3DMsoNormal =
style=3D'margin-left:36.0pt;background:white'><span lang=3DEN-GB =
style=3D'font-size:10.5pt;font-family:"Helvetica",sans-serif;color:red;ms=
o-fareast-language:IT'>if preceded =
by <b><i>abil</i></b>, <b><i>ic</i></b> or <b><i>iv</=
i></b>, delete if in <i>R</i>2<o:p></o:p></span></p><p =
class=3DMsoNormal>And in step 3 there is the rule:<o:p></o:p></p><p =
class=3DMsoNormal><span lang=3DEN-GB =
style=3D'font-size:10.5pt;font-family:"Helvetica",sans-serif;color:red;ms=
o-fareast-language:IT'>Delete a =
final <b><i>a</i></b>, <b><i>e</i></b>, <b><i>i</i></b>,&n=
bsp;<b><i>o</i></b>, <b><i>=C3=A0</i></b>, <b><i>=C3=A8</i></b>=
, <b><i>=C3=AC</i></b> or <b><i>=C3=B2</i></b> if it =
is in <i>RV</i>, and a preceding <b><i>i</i></b> if it is =
in <i>RV</i> </span><o:p></o:p></p><p class=3DMsoNormal>In =
step 1 I delete =E2=80=9Cabilit=C3=A0=E2=80=9D and the word becomes =
=E2=80=9Cpratic=E2=80=9D<o:p></o:p></p><p =
class=3DMsoNormal><o:p> </o:p></p><p class=3DMsoNormal>I leave RV =
untouched, and so it is still =
=E2=80=9Cticabilit=C3=A0=E2=80=9D<o:p></o:p></p><p =
class=3DMsoNormal><o:p> </o:p></p><p class=3DMsoNormal>In step 3 I =
search for =E2=80=9C=C3=A0=E2=80=9D in RV and I found it as last =
character.<o:p></o:p></p><p class=3DMsoNormal>So I think I have to =
delete 1 character and I delete wrongly =
=E2=80=9Cc=E2=80=9D<o:p></o:p></p><p =
class=3DMsoNormal><o:p> </o:p></p><p class=3DMsoNormal>I wonder =
which the correct algorithm is. Maybe I need to delete matches from R1, =
R2, and RV too?<o:p></o:p></p><p class=3DMsoNormal>Thanks in advance for =
your help.<o:p></o:p></p><p class=3DMsoNormal>Alfonso<o:p></o:p></p><p =
class=3DMsoNormal><o:p> </o:p></p><p class=3DMsoNormal><b><span =
style=3D'font-size:10.0pt;color:#E05661;mso-fareast-language:IT'>Alfonso =
Moscato</span></b><span =
style=3D'font-size:10.0pt;color:#E05661;mso-fareast-language:IT'><br></sp=
an><i><span style=3D'mso-fareast-language:IT'>CIO & =
COO</span></i><span =
style=3D'font-size:9.0pt;color:black;mso-fareast-language:IT'><br></span>=
<i><span style=3D'mso-fareast-language:IT'>Merqurio =
Holding</span></i><span =
style=3D'mso-fareast-language:IT'><br>Corso Umberto I, 23&=
nbsp;- 80138 Napoli<br><i>Tel.+39 0815524300 </i><br>=
<i>Fax.+39 0814201136 </i><br><i>Linea Verde: +39&nbs=
p;800014863 </i><br> <br>Diretto. +39 081 =
96.336.22 <br>Mobile. +39 348 =
36.79.384<o:p></o:p></span></p><p class=3DMsoNormal><span =
style=3D'font-size:9.0pt;color:black;mso-fareast-language:IT'><o:p> =
</o:p></span></p><p class=3DMsoNormal><span =
style=3D'mso-fareast-language:IT'><o:p> </o:p></span></p><p =
class=3DMsoNormal><span =
style=3D'mso-fareast-language:IT'><o:p> </o:p></span></p><p =
class=3DMsoNormal><span =
style=3D'mso-fareast-language:IT'><o:p> </o:p></span></p><p =
class=3DMsoNormal><o:p> </o:p></p></div></body></html>
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