Re: Raw Payload Expressions - out of bounds write?

> this is in bits.

> [ payload load 1 byte @ inner header + 6 bytes => reg 1 ]
> [ bitwise reg 1 = ( reg 1 & 0xc0 ) ]
> [ payload write reg 1 => 1 byte @ inner header + 6 bytes ... ]

haha

[ payload load 1 byte (8 bits) @ inner header + 7 bytes (56 bits) => reg 1 ]
[ bitwise reg 1 = ( reg 1 & 0xc0 ) ]
[ payload write reg 1 => 1 byte (8 bits) @ inner header + 7 bytes (56 bits) ... ]

I suppose you are correct there, I forgot to adjust the offset.

sunny