Re: [PATCH] Fix bang flag in ${(!)ref::=var} substitutions

On Fri, Jul 10, 2026 at 5:06=E2=80=AFAM Philippe Altherr
<[email protected]> wrote:
>
> The documentation states that with the substitution flag (!) the referenc=
e itself is examined, not its referent, but this fails in ${(!)ref::=3Dvar}=
 substitutions:

I'm unsure what to do with this one.

Ksh doesn't have ${x::=3Dy} so there's no direct comparison.

With "ref" undeclared or with `typeset -n ref` (placeholder),
${!ref:=3Dvar} ksh always returns "ref" and ignores the assignment.

So we're in a bit of uncharted territory here.  It's not clear that
::=3D should alter "ref".

Is this a precedence issue?  I.e., should ${(!)ref::=3Dvar} be
equivalent to ${(!)${ref::=3Dvar}} ?  (Which is the current behavior,
right?)