Re: [dk-tug] babyloniannum (rettelse)
Poul Riis <[email protected]> Wed, 16 Mar 2016 13:44:42 +0100
| Newsgroups | gmane.comp.tex.danish |
|---|---|
| Message-ID | <[email protected]> |
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Nu virker nedenstående på min computer.
Tilbage står bare, at jeg gerne vil have tabu yderst, så der bliver tale
om én samlet tabel. Det kan jeg ikke få til at fungere.
Poul Riis
\documentclass[a4paper]{article}
\usepackage{pgffor}
\usepackage{babyloniannum}
\usepackage{multido}
\usepackage{tikz}
\usepackage{tabu}
\renewcommand{\babylonianfont}{Santakku.ttf}
\begin{document}
~\\
\foreach \x in {1,...,30} {
\pgfmathsetmacro\result{int(9*\x)}
\begin{tabu} to 4cm {X[2,c] X[2,c]}
\babyloniannum{\x} & \babyloniannum{\result}
\end{tabu}\\
}
\end{document}
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l=22 size=3D=22+0=22 color=3D=22=23000000=22 style=3D=22font-family:Arial;f=
ont-size:10pt;color:=23000000;=22>Nu virker nedenst=C3=A5ende p=C3=A5 min c=
omputer.</font></div>
<br />
<div align=3D=22left=22 style=3D=22text-align:left;=22><font face=3D=22Aria=
l=22 size=3D=22+0=22 color=3D=22=23000000=22 style=3D=22font-family:Arial;f=
ont-size:10pt;color:=23000000;=22>Tilbage st=C3=A5r bare, at jeg gerne vil =
have tabu yderst, s=C3=A5 der bliver tale om =C3=A9n samlet tabel. Det kan =
jeg ikke f=C3=A5 til at fungere.</font></div>
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