[dk-tug] Opgave-environment
Poul Riis <[email protected]> Tue, 12 Feb 2019 11:40:35 +0100
| Newsgroups | gmane.comp.tex.danish |
|---|---|
| Message-ID | <[email protected]> |
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Sommetider bruger jeg det opgave-environment (som jeg vistnok har fået
fra daleif), der i lidt ændret form ses i nedenstående.
De ændringer, jeg har lavet, skyldes, at STX-opgavekommissionens opgaver
nu har ændret lidt form:
Nu gives der enten 5 eller 10 points i hvert delspørgsmål, og
pointstallet kan være farvet, hvis der er tale om en såkaldt
mindstekravsopgave.
Jeg er dog ikke tilfreds med mine ændringer.
Kan man lave det på en smart måde, så man i hvert delspørgsmål
angiver pointtal og farve, og så antallet af tildelte points kumuleres
løbende?
Poul Riis
\documentclass[12pt,a4paper]{article}
\usepackage[latin1]{inputenc}
\usepackage[T1]{fontenc}
\usepackage[danish]{babel}
\usepackage{amsmath}
\usepackage{environ}
\usepackage{enumitem}
\usepackage[dvips,left=2cm,top=1.75cm,right=2.5cm,bottom=2.25cm]{geometry}
\usepackage[dvips,x11names]{xcolor}
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\def\hest{}
\newcommand\CallBack[1]{\renewcommand\hest{#1}}
\makeatletter
\newenvironment{opgave}{%
\setcounter{enumi}{0}%
\Collect@Body{\CallBack}%
}{%
\stepcounter{nopg}%
\parbox[t]{2.5cm}{\bf Opgave \the\value{nopg}}%
\parbox[t]{15cm}{\hest}%
\ifnum\value{enumi}=0\relax%
\stepcounter{nsp}%
\else%
\addtocounter{nsp}{\theenumi}%
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}
\makeatother
\newcounter{nopg}[enumii]
\setcounter{nopg}{0}
\newcounter{nsp}
\setcounter{nsp}{0}
\begin{document}
\section*{Matematikopgaver}
\begin{opgave}
En cirkel har centrum i punktet $C(-2,3)$ og går gennem punktet $P(1,7)$.
\begin{enumerate}[leftmargin=8mm,label=(10 points)\hspace{10mm}(\alph*)]
\item Bestem en ligning for tangenten til cirklen i punktet $P$.
\end{enumerate}
\end{opgave}
\begin{opgave}
En funktion $f$ har forskriften $f(x)=x\ln(x)$.
\begin{enumerate}[leftmargin=8mm,label=
\fcolorbox{OliveDrab3}{OliveDrab3}{(5 points)}\hspace{10mm}(\alph*)]
\item Bestem en ligning for tangenten til grafen for $f$ i punktet
$(1,f(1))$.
\end{enumerate}
\begin{enumerate}[resume,label=(10 points)\hspace{10mm}(\alph*)]
\item Bestem...
\end{enumerate}
\end{opgave}
\end{document}
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<body marginleft=3D=2210=22 marginright=3D=2210=22 margintop=3D=2210=22 mar=
ginbottom=3D=2210=22>
<div align=3D=22left=22 style=3D=22text-align:left;=22><font face=3D=22Aria=
l=22 size=3D=22+0=22 color=3D=22=23000000=22 style=3D=22font-family:Arial;f=
ont-size:10pt;color:=23000000;=22>Sommetider bruger jeg det opgave-environm=
ent (som jeg vistnok har f=C3=A5et fra daleif), der i lidt =C3=A6ndret form=
ses i nedenst=C3=A5ende.</font></div>
<div align=3D=22left=22 style=3D=22text-align:left;=22><font face=3D=22Aria=
l=22 size=3D=22+0=22 color=3D=22=23000000=22 style=3D=22font-family:Arial;f=
ont-size:10pt;color:=23000000;=22>De =C3=A6ndringer, jeg har lavet, skyldes=
, at STX-opgavekommissionens opgaver nu har =C3=A6ndret lidt form:</font></=
div>
<div align=3D=22left=22 style=3D=22text-align:left;=22><font face=3D=22Aria=
l=22 size=3D=22+0=22 color=3D=22=23000000=22 style=3D=22font-family:Arial;f=
ont-size:10pt;color:=23000000;=22>Nu gives der enten 5 eller 10 points i hv=
ert delsp=C3=B8rgsm=C3=A5l, og pointstallet kan v=C3=A6re farvet, hvis der =
er tale om en s=C3=A5kaldt mindstekravsopgave.</font></div>
<div align=3D=22left=22 style=3D=22text-align:left;=22><font face=3D=22Aria=
l=22 size=3D=22+0=22 color=3D=22=23000000=22 style=3D=22font-family:Arial;f=
ont-size:10pt;color:=23000000;=22>Jeg er dog ikke tilfreds med mine =C3=A6n=
dringer.</font></div>
<div align=3D=22left=22 style=3D=22text-align:left;=22><font face=3D=22Aria=
l=22 size=3D=22+0=22 color=3D=22=23000000=22 style=3D=22font-family:Arial;f=
ont-size:10pt;color:=23000000;=22>Kan man lave det p=C3=A5 en smart m=C3=
=A5de, s=C3=A5 man i hvert delsp=C3=B8rgsm=C3=A5l angiver pointtal og farve=
, og s=C3=A5 antallet af tildelte points kumuleres l=C3=B8bende?</font></di=
v>
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l=22 size=3D=22+0=22 color=3D=22=23000000=22 style=3D=22font-family:Arial;f=
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ont-size:10pt;color:=230000DD;=22>=5Csection*=7BMatematikopgaver=7D</font><=
/div>
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<div align=3D=22left=22 style=3D=22text-align:left;=22><font face=3D=22Aria=
l=22 size=3D=22+0=22 color=3D=22=230000DD=22 style=3D=22font-family:Arial;f=
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<div align=3D=22left=22 style=3D=22text-align:left;=22><font face=3D=22Aria=
l=22 size=3D=22+0=22 color=3D=22=230000DD=22 style=3D=22font-family:Arial;f=
ont-size:10pt;color:=230000DD;=22>En cirkel har centrum i punktet =24C(-2,3=
)=24 og g=C3=A5r gennem punktet =24P(1,7)=24. </font></div>
<div align=3D=22left=22 style=3D=22text-align:left;=22><font face=3D=22Aria=
l=22 size=3D=22+0=22 color=3D=22=230000DD=22 style=3D=22font-family:Arial;f=
ont-size:10pt;color:=230000DD;=22>=5Cbegin=7Benumerate=7D=5Bleftmargin=3D8m=
m,label=3D(10 points)=5Chspace=7B10mm=7D(=5Calph*)=5D</font></div>
<div align=3D=22left=22 style=3D=22text-align:left;=22><font face=3D=22Aria=
l=22 size=3D=22+0=22 color=3D=22=230000DD=22 style=3D=22font-family:Arial;f=
ont-size:10pt;color:=230000DD;=22>  =
; =5Citem Bestem en ligning for tangenten til cirklen i punktet =24P=
=24.</font></div>
<div align=3D=22left=22 style=3D=22text-align:left;=22><font face=3D=22Aria=
l=22 size=3D=22+0=22 color=3D=22=230000DD=22 style=3D=22font-family:Arial;f=
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<div align=3D=22left=22 style=3D=22text-align:left;=22><font face=3D=22Aria=
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ont-size:10pt;color:=230000DD;=22>=5Cend=7Bopgave=7D</font></div>
<div align=3D=22left=22 style=3D=22text-align:left;=22><font face=3D=22Aria=
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ont-size:10pt;color:=230000DD;=22>=5Cbegin=7Bopgave=7D</font></div>
<div align=3D=22left=22 style=3D=22text-align:left;=22><font face=3D=22Aria=
l=22 size=3D=22+0=22 color=3D=22=230000DD=22 style=3D=22font-family:Arial;f=
ont-size:10pt;color:=230000DD;=22>En funktion =24f=24 har forskriften =24f(=
x)=3Dx=5Cln(x)=24. </font></div>
<div align=3D=22left=22 style=3D=22text-align:left;=22><font face=3D=22Aria=
l=22 size=3D=22+0=22 color=3D=22=230000DD=22 style=3D=22font-family:Arial;f=
ont-size:10pt;color:=230000DD;=22>=5Cbegin=7Benumerate=7D=5Bleftmargin=3D8m=
m,label=3D =5Cfcolorbox=7BOliveDrab3=7D=7BOliveDrab3=7D=7B(5 points)=7D=5Ch=
space=7B10mm=7D(=5Calph*)=5D</font></div>
<div align=3D=22left=22 style=3D=22text-align:left;=22><font face=3D=22Aria=
l=22 size=3D=22+0=22 color=3D=22=230000DD=22 style=3D=22font-family:Arial;f=
ont-size:10pt;color:=230000DD;=22>  =
; =5Citem Bestem en ligning for tangenten til grafen for =24f=24 i pun=
ktet =24(1,f(1))=24.</font></div>
<div align=3D=22left=22 style=3D=22text-align:left;=22><font face=3D=22Aria=
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