Issue with Related Post Javascript in Blogger

I have created a related post javascript for blogger.com based blogs. The 
related post plugins loops though the label attached to the current post 
and displays other posts with the same label.


You can find that in action @ 
http://www.techquark.com/2017/07/infocus-turbo-5-affordable-powerful.html


The issue is I want to skip the current post to be shown in the related 
post, but unable to achieve the same.


PFB the javascript code :


$(".related-ready").each(function() {
    var b = $(this).text();
    $.ajax({
        url: "/feeds/posts/default/-/" + b + "?alt=json-in-script&max-results=3",
        type: 'get',
        dataType: "jsonp",
        success: function(e) {
            var u = "";
            var h = '<div class="related">';
            for (var i = 0; i < e.feed.entry.length; i++) {
                for (var j = 0; j < e.feed.entry[i].link.length; j++) {
                    if (e.feed.entry[i].link[j].rel == "alternate") {
                        u = e.feed.entry[i].link[j].href;
                        break
                    }
                }
                var g = e.feed.entry[i].title.$t;
                var c = e.feed.entry[i].content.$t;
                var $c = $('<div>').html(c);
                if (c.indexOf("//www.youtube.com/embed/") > -1) {
                    var p = e.feed.entry[i].media$thumbnail.url;
                    var k = p
                } else if (c.indexOf("<img") > -1) {
                    var q = $c.find('img:first').attr('src');
                    var k = q
                } else {
                    var k = NO_IMAGE
                }
                h += '<li><div class="related-thumb"><a class="related-img" href="' + u + '" style="background:url(' + k + ') no-repeat center center;background-size: cover"/></div><h3 class="related-title"><a href="' + u + '">' + g + '</a></h3></li>'
            }
            h += '</div><div class="clear"/>';
            $(".related-ready").html(h);
            $('.related-img').each(function() {
                $(this).attr('style', function(i, src) {
                    return src.replace('/default.jpg', '/hqdefault.jpg')
                }).attr('style', function(i, src) {
                    return src.replace('s72-c', 's1600')
                })
            })
        }
    })});


TIA !

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