Re: how to break out of FCGX_Accept_r

Andrej van der Zee <andrej@...> writes:

> 
> Hi,
> 
> I would like to know if it is possible to break out of the pending 
> accept-call and how to do this. The problem is, I have to shutdown the 
> fast-cgi after it has been runnig for 8 hours. In c++, when I schedule a 
> threat that wakes up after 8 hours, the fast-cgi main-loop can be in two 
> situations:
> 1) It is handling a request. In this case the fast-cgi should finish 
> after handling it. This can be done with FCGX_ShutdownPending(). No 
> problem here.
> 2) The main-loop is in FCGX_Accept_r waiting for an incomming 
> connection. In this case I would like to break out of the accept and 
> immideately finish the fast-cgi application.
> 
> In the threat that wakes up after 8 hours, I was thinking to raise a 
> signal in case 2 only. Though, how can I be sure that we are in case 2? 
> Setting flags before entering and after leaving FCGX_Accept_r is not 
> sufficient because my treat may wakeup when fast-cgi already accpeted a 
> request, but has not come out of FCGX_Accept_r yet.
> 
> Any ideas? Any other solutions?
> 
> Thanks a bunch!
> 
> Andrej
> ___________________________________
> fastcgi-developers mailing list
> http://fastcgi.com/fastcgi-developers/
> 
> 

Hi,

The FCGX_Accept_r( &request ) breaks out of it's internal socket listener loop 
occasionally; I think it's every 100ms but you will need to check the source 
code.

To cause the FCGX_Accept_r call to exit before a new request has arrived, call 
FCGX_ShutdownPending();

providing your Accept_r loop is like this:

while( (FCGX_Accept_r( &request ) >= 0)  ){ 

your application will not try to process the null &request pointer.

Kind regards

Michael Hartley.

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