Re: Re: how to break out of FCGX_Accept_r

Hi,

Thanks for your reply.

I experimented with your approach but it does not break out of the 
blocking accept call (in Linux). On what platform did you test this?

Cheers,

Andrej

Michael Hartley wrote:

>Andrej van der Zee <andrej@...> writes:
>
>  
>
>>Hi,
>>
>>I would like to know if it is possible to break out of the pending 
>>accept-call and how to do this. The problem is, I have to shutdown the 
>>fast-cgi after it has been runnig for 8 hours. In c++, when I schedule a 
>>threat that wakes up after 8 hours, the fast-cgi main-loop can be in two 
>>situations:
>>1) It is handling a request. In this case the fast-cgi should finish 
>>after handling it. This can be done with FCGX_ShutdownPending(). No 
>>problem here.
>>2) The main-loop is in FCGX_Accept_r waiting for an incomming 
>>connection. In this case I would like to break out of the accept and 
>>immideately finish the fast-cgi application.
>>
>>In the threat that wakes up after 8 hours, I was thinking to raise a 
>>signal in case 2 only. Though, how can I be sure that we are in case 2? 
>>Setting flags before entering and after leaving FCGX_Accept_r is not 
>>sufficient because my treat may wakeup when fast-cgi already accpeted a 
>>request, but has not come out of FCGX_Accept_r yet.
>>
>>Any ideas? Any other solutions?
>>
>>Thanks a bunch!
>>
>>Andrej
>>___________________________________
>>fastcgi-developers mailing list
>>http://fastcgi.com/fastcgi-developers/
>>
>>
>>    
>>
>
>Hi,
>
>The FCGX_Accept_r( &request ) breaks out of it's internal socket listener loop 
>occasionally; I think it's every 100ms but you will need to check the source 
>code.
>
>To cause the FCGX_Accept_r call to exit before a new request has arrived, call 
>FCGX_ShutdownPending();
>
>providing your Accept_r loop is like this:
>
>while( (FCGX_Accept_r( &request ) >= 0)  ){ 
>
>your application will not try to process the null &request pointer.
>
>Kind regards
>
>Michael Hartley.
>
>
>
>
>
>  
>
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