Re: running code after FCGX_Accept fails

I guess this is because FCGX_Accept is a blocking function, so the
probability that your program was blocked at this very line when killed by
apache is high.
When Apache shuts it down, it might send a signal, which you could intercept
and run the cleanup code before exiting yourself from the code.

Regards,
Etienne.

On 7/27/07, alexander johnson <[email protected]> wrote:
>
> Hi,
> Sorry if I was unclear, given the following code:
>
> void main()
> {
> //initialization code
>
> while(FCGX_Accept( &in, &out, &err, &envp ) >=0)    <---- (1)
> {
> processRequests();
>
> }
> cleanup();                          <----- (2)
>
> }//end of program
>
> My code will happily run through the while loop above while my program
> is still running.  My problem is that when my program stops running
> say due to Apache shutting down or closing the fcgi, my code never
> gets as far as the cleanup() function (2).  When apache terminates the
> fcgi, my code exits at (1) so never makes it to (2).  I need to run
> (2) before the program exits.  No matter what way the fcgi is
> terminated it will always exit at (1)
>
>
> Thanks
>
> Alex
>
> On 7/27/07, Sven Verdoolaege <[email protected]> wrote:
> > On Thu, Jul 26, 2007 at 04:51:02PM +0100, alexander johnson wrote:
> > > Hi,
> > > There some very important cleanup code i need to run after FCGX_Accept
> > > == -1 and exits its loop.  The problem is that the program exits
> > > immediately after FCGX_Accept == -1 so  cant run any code after.
> >
> > You'll have to be a bit more specific.  Are you saying that FCGX_Accept
> > never returns and just exists or that your code exits after FCGX_Accept
> > returns?  In the latter case, there's not much we can do to help you.
> >
> > In any case, FCGX_Accept does not return -1, unless the error happens
> > to be EPERM.  Why do you think it does?
> >
> > skimo
> >
>
>
> --
> Alex
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> http://fastcgi.com/fastcgi-developers/
>

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