compiling apache 2.2.8 with --with-module=mod_fastcgi (brakes)

hello everyone,
I've just subscribed, greetings to all

could compilation like above be done?
what I do I copy -a mod_fastcgi-2.4.6 into $archive-untared/modules and 
then rename
mod_fastcgi-2.4.6 to mod_fastcgi
I amend Makefile after I created it by copying Makefile.AP2, I change: 
top_dir, (obviously)
and.. when I apache's ./configure --prefix=/opt --with-mpm=worker 
--enable-so --enable-rewrite --enable-module=so 
--with-module=mod_fastcgi --enable-module=deflate, script complains:
cat: /install/apache/httpd-2.2.8/modules/mod_fastcgi/Makefile.in: No 
such file or directory

after apache's ./configure Makefile in modules/mod_fastcgi looks like this:
top_srcdir   = /install/apache/httpd-2.2.8
top_builddir = /install/apache/httpd-2.2.8
srcdir       = /install/apache/httpd-2.2.8/modules/mod_fastcgi
builddir     = /install/apache/httpd-2.2.8/modules/mod_fastcgi
VPATH        = /install/apache/httpd-2.2.8/modules/mod_fastcg

then 'make'ing apache brakes:
Making all in mod_fastcgi
make[2]: Entering directory 
`/install/apache/httpd-2.2.8/modules/mod_fastcgi'
make[2]: *** No rule to make target `all'.  Stop.
make[2]: Leaving directory `/install/apache/httpd-2.2.8/modules/mod_fastcgi'

so I cat Makefile.AP2 >> Makefile and run apache's make
(this same becomes the case when I satisfy ./configure by making copy of 
Makefile.AP2 with name Makefile.in)
and then:

make[1]: Entering directory `/install/apache/httpd-2.2.8'
make[1]: *** No rule to make target 
`modules/mod_fastcgi/libmod_fasgi.la', needed by `httpd'.  Stop.
make[1]: Leaving directory `/install/apache/httpd-2.2.8

can anyone tell what I'm ./configuring wrongly here?
cheers


	
	
		
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