Re: Comments merging, pass 2

Various people wrote:
> Logically, though, "return (a and [b] or [c])[0]" has to be one
> dictionary allocation larger than
> 
> if a: return b
> else: return c

Not if the list is lazily evaluated (as it indeed is in Python).

Both cases evaluate a.  If a is false, then a and [b] has to be false, 
so [b] doesn't even get constructed, and it skips to the "or [c]".  On 
the other hand, if a is true, then "a and [b]" will be true, so [c] 
doesn't get evaluated, since true or anything is still true.

Later,
Blake.


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