Re: Variable references in path expressions

>
> With a QName on the right, interpreting $a/xs:QName($b) to mean
> $a/*[node-name()=xs:QName($b)] would make no sense at all in terms of "/" as
> a mapping operator. Of course one could have overloaded the "/" operator
> that way, but it would not have been a logical extension to the XPath 1.0
> meaning, and it would only create a shorter way of writing something that
> can already be written with a predicate.
>
You are correct. I can now sleep in peace :)