Re: Warning: Unreachable code detected

The compiler warning is given in that the break statement is unreachable
code irrespective of the default case.

On Nov 12, 2007 11:20 AM, Bhatnagar, Amit <[email protected]>
wrote:

> try:
>
>        case 3:
>                throwException = true;
>                break;
>
>        (you should always have a default case)
>        default:
>                assert(false); //unhandled case
>                break;
>
> if (throwException)
> {
>        throw new ApplicationException("No such logon session.")
> }
>
>  -----Original Message-----
> From: Discussion forum for developers using Windows Forms to build apps
> and controls [mailto:[email protected]] On Behalf Of
> R. Rogers
> Sent: Monday, November 12, 2007 10:15 AM
> To: [email protected]
> Subject: [DOTNET-WINFORMS] Warning: Unreachable code detected
>
> Hi,
>
> I like coding defensively, and correct me if I'm wrong, but I think the
> following code demonstrates this to a very small degree:
>
>            switch (code)
>            {
>                case 1:
>                    result = DialogResult.OK;
>                    break;
>
>                case 2:
>                    result = DialogResult.Cancel;
>                    break;
>
>                case 3:
>                    throw new ApplicationException("No such logon
> session.");
>                    break;
>
>        ...
>        }
>
> The trouble is that if I break after throwing an exception, the compiler
> gives me an "unreachable code detected" message, and I don't like any
> warnings.
>
> Would you have any advice to share on this? I don't really want to get
> rid of the break statement.
>
> Best regards,
>
> Richard Rogers
> http://www.RichardRogers.ca/ <http://www.richardrogers.ca/>
>
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